All categories

3 years ago

Choose the correct simplification of the expression (3x - 6)(2x^2 - 4x - 5) ?

Mathematics

2 answers:

topjm [15]3 years ago

7 0

= 3x(2x^2 - 4x - 5) - 6(2x^2 - 4x - 5)

= 6x^3 - 12x^2 - 15x - 12x^2 + 24x + 30

= 6x^3 - 24x^2 + 9x + 30 (answer)

emmasim [6.3K]3 years ago

7 0

Answer:

6x³ -24x² - 9x + 30

Step-by-step explanation:

For the simplification of such equations, we use the VBODMAS method.

This means first we simplify V i.e. Vinculum or Bar

then B i.e. Brackets,

O i.e. order of exponent roots

D i.e. division

M i.e. multiplication

A i.e. addition

S i.e. subtraction

Now, solving given expression,

(3x - 6)(2x² - 4x - 5)

= 6x³ - 12x² - 15x -12x² + 24x + 30 { We mulplied both brackets term}

{ Also, xᵃ × xᵇ = xᵃ⁺ᵇ }

= 6x³ -24x² - 9x + 30

You might be interested in

You are given the parametric equations x=2cos(θ),y=sin(2θ). (a) List all of the points (x,y) where the tangent line is horizonta

vladimir1956 [14]

Answer:

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

Step-by-step explanation:

The slope of the tangent line at a point of the curve is:

$m = \frac{\frac{dy}{dt} }{\frac{dx}{dt} }$

$m = -\frac{\cos 2\theta}{\sin \theta}$

The tangent line is horizontal when $m = 0$ . Then:

$\cos 2\theta = 0$

$2\theta = \cos^{-1}0$

$\theta = \frac{1}{2}\cdot \cos^{-1} 0$

$\theta = \frac{1}{2}\cdot \left(\frac{\pi}{2}+i\cdot \pi \right)$ , for all $i \in \mathbb{N}_{O}$

$\theta = \frac{\pi}{4} + i\cdot \frac{\pi}{2}$ , for all $i \in \mathbb{N}_{O}$

The first four solutions are:

x: $\sqrt{2}$ $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$

y: 1 -1 1 -1

The solutions listed from the smallest to the greatest are:

x: $-\sqrt{2}$ $-\sqrt{2}$ $\sqrt{2}$ $\sqrt{2}$

y: -1 1 -1 1

6 0

2 years ago

If zb⊥ya , find m<br><br>A. 28<br><br>B.46<br><br>C.56<br><br>D.62<br><br>I'll give you brainliest

prohojiy [21]

<h3>Answer:</h3>

A. 28

<h3>Step-by-step explanation:</h3>

We assume m is the measure of the marked unknown angles: ∠BZY ≅ ∠BZA

(5x +3)° = (2x +18)°

Divide by ° and subtract 2x+3:

... 3x = 15

... x = 5

Then ∠BZA = (2·5 +18)° = m = 28°

5 0

3 years ago

Bamboo Plant A is 1.2 meters tall and growing at a rate of 0.45 meter per day. Bamboo Plant B is 0.85 meter tall and growing 0.5

pashok25 [27]

Answer:

7 days

Step-by-step explanation:

Bamboo plant A = 1.2 + 0.45d

Bamboo plant B = 0.85 + 0.5d

Where,

d = number of days

Equate the two growth

Bamboo plant A = Bamboo plant B

1.2 + 0.45d = 0.85 + 0.5d

Collect like terms

1.2 - 0.85 = 0.5d - 0.45d

0.35 = 0.05d

Divide both sides by 0.05

d = 0.35 / 0.05

d = 7 days

Plant B be taller than Plant A after 7 days

3 0

2 years ago

Which of the following ratios is used in finding the sine of an angle in a right triangle?

stira [4]

The ratio is called the Opposite leg or also known as Hypotenuse. Usually, in a right angle, the size of the one angle is 90 degrees while the other which is less than 90 degrees is called the hypotenuse. It is the opposite side of the angle measured 90 degrees

3 0

3 years ago

13.48x - 200 < 256.12

podryga [215]

Answer:

x < 33.84

Step-by-step explanation:

we have

13.48x-200 < 256.12

Solve for x

Adds 200 both sides

13.48x-200 +200 < 256.12+200

13.48x < 456.12

Divide by 13.48 both sides

13.48x/13.48 < 456.12/13.48

x < 33.84

The solution is the interval ----> (-∞, 33.84)

All real numbers less than 33.84

5 0

3 years ago