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Liula [17]
4 years ago
14

Find the work done by the gas during the following stages. (a) A gas is expanded from a volume of 1.000 L to 4.000 L at a consta

nt pressure of 2.000 atm. (b) The gas is then cooled at constant volume until the pressure falls to 1.500 atm
Physics
1 answer:
netineya [11]4 years ago
7 0

Answer:

<em>a) 607.95 J</em>

<em>b) 0 J</em>

<em></em>

Explanation:

a) Initial volume = 1 L = 0.001 m^3

final volume = 4 L = 0.004 m^3

pressure = 2 atm = 202650 Pa     (1 atm = 101325 Pa)

work done by the gas on the environment = PΔV

P is the pressure = 101325 Pa

ΔV is the change in volume from the initial volume to the final volume

ΔV = 0.004 m^3 - 0.001 m^3 = 0.003 m^3

work done by the gas = 202650 x 0.003 = <em>607.95 J</em>

b) If the gas is cooled at constant volume, then the gas does no work. For a gas to do work, there must be a change in its volume.

Therefore the work done in cooling at constant volume until pressure falls to 1.5 atm = <em>0 J</em>

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3 years ago
Find the heat given off if 1 kg of 125 degree C steam is cooled to 50 degree C water.
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\\ \sf{:}\Rrightarrow Q=mc\Delta T

\\ \sf{:}\Rrightarrow Q=1(4184)(75)

\\ \sf{:}\Rrightarrow Q=313800J

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Answer:

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Considering the condition of Bragg's law:

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2dsinθ = hc/EK - EL

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Where 'd' is the separation distance between the parallel planes of an atom, 'h' is the Planck's constant, 'c' is the velocity of light, θ is the angle of reflection, 'EK' is the energy of the K shell and 'EL' is the energy of the K shell.

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R = 1.15 * 10^-8 ohms. <<<< Answer

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