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kakasveta [241]
3 years ago
13

Do you support trucks are identical each box loaded on the truck has the same mask choose the truck that has the greatest force

of gravity acting on it?helpppppp

Physics
1 answer:
Anestetic [448]3 years ago
7 0

gravitational force of earth is given by

F = mg

so here the force will depend on the product of mass and gravity

so here force will be more if we took the condition of more masses

so here in 3rd figure

there will be maximum force of gravity on it

because it will have 6 boxes so there will be maximum mass

So figure of truck with 6 boxes on it is correct answer

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A chemical property of gasoline is that it will burn in air. Gasoline is a substance that is used to power automobiles. Gasoline will oxidize in air which means that it reacts with oxygen in air. Hope this answers the question. Have a nice day.
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After a long day you go home in your friend's really fancy sports car which has a sun-roof on the top and a spoiler (a little wi
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Answer:

B: air pressure inside the car drops suddenly

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An amusement park ride consists of a large vertical cylinder that spins about its axis fast enough that a person inside is stuck
ElenaW [278]

Let N be the normal force that forces the person against the wall.

Then u N = m g  is the frictional force supporting the person's weight

and N = m g / u

also, N = m v^2 / R is the normal force providing the centripetal acceleration

So, m g / u = m v^2 / R

v^2 = g R / u

since v = 2 pi R T

4 pi^2 R^2 T^2 = g R / u     and T^2 = g / (4  u pi^2 R)

T = 1/ (2 pi)  (g /(u R))^1/2 = .159 * (9.8 m/s^2 / (.521 * 4.4 m)) ^1/2

T = .68 / s

Do you see any thing wrong here?

T should have units of seconds not 1 / seconds

v should be  2 * pi * R / T  where T is the time for 1 revolution

So you need to make that correction in the above formula for v.

7 0
3 years ago
An unstable particle at rest spontaneously breaks into two fragments of unequal mass. The mass of the first fragment is 3.00 10-
kirill [66]

Answer:0.478 c

Explanation:

Given

mass of lighter Particle(m_1)=3\times 10^{-28} kg

mass of heavier Particle(m_2)=1.51\times 10^{-27} kg

speed of lighter particle(v_1)=0.834 c

Let speed of heavier particle=v_2

and Momentum of the particle is given by

P=\frac{mv}{\sqrt{1-(\frac{v}{c})^2}}

P_1=\frac{m_1v_1}{\sqrt{1-(\frac{v_1}{c})^2}}

P_1=\frac{3\times 10^{-28}\times 0.834 c}{\sqrt{1-(\frac{0.834 c}{c})^2}}

P_1=8.219\times 10^{-28} kg c

P_2=\frac{m_2v_2}{\sqrt{1-(\frac{v_2}{c})^2}}

as momentum is conserved therefore P_1=P_2

8.219\times 10^{-28} kg c=\frac{1.51\times 10^{-27}\times v_2}{\sqrt{1-(\frac{v_2}{c})^2}}

v_2=0.478 c

3 0
3 years ago
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