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4 years ago

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What are the lengths of the legs of a right triangle in which one acute angle measures 19° and the hypotenuse is 15 units long?

2 answers:

stich3 [128]4 years ago

8 0

The legs of a triangle with a hypotenuse that measures 15 units long have lengths that are equal to 15 times the sine or cosine of the given angle.
leg 1 = (15 units) x (cos 19) = 14.18 units
leg 2 = (15 units) x (sin 19) = 4.88 units
The lengths of the legs are 14.18 units and 4.88 units.

Anarel [89]4 years ago

3 0

The side opposite the angle 19 degrees is given by 15sin 19 = 4.9 units, while the side adjacent the angle 19 degrees is given by 15cos 19 = 14.2 units.

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If K is the midpoint of JL, JK = 8x + 11 and KL = 14x – 1, find JL.

masha68 [24]

Answer:

$JL=54$

Step-by-step explanation:

We are given that K is the midpoint of JL. Using this information, we want to find JL.

By the definition of midpoint, this means that:

$JK=KL$

Substitute them for their equations:

$8x+11=14x-1$

Solve for <em>x.</em> Subtract 8<em>x</em> from both sides:

$11=6x-1$

Add 1 to both sides:

$6x=12$

And divide both sides by 6. Hence:

$x=2$

JL is the sum of JK and KL. Hence:

$JK+KL=JL$

Since JK = KL, substitute either one for the other:

$JK+(JK)=2JK=JL$

Substitute JK for its equation:

$2(8x+11)=JL$

Since we know that <em>x</em> = 2:

$2(8(2)+11)=2(16+11)=2(27)=54=JL$

Thus:

$JL=54$

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3 years ago

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Answer:

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Step-by-step explanation:

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