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3 years ago

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What are the lengths of the legs of a right triangle in which one acute angle measures 19° and the hypotenuse is 15 units long?

2 answers:

stich3 [128]3 years ago

8 0

The legs of a triangle with a hypotenuse that measures 15 units long have lengths that are equal to 15 times the sine or cosine of the given angle.
leg 1 = (15 units) x (cos 19) = 14.18 units
leg 2 = (15 units) x (sin 19) = 4.88 units
The lengths of the legs are 14.18 units and 4.88 units.

Anarel [89]3 years ago

3 0

The side opposite the angle 19 degrees is given by 15sin 19 = 4.9 units, while the side adjacent the angle 19 degrees is given by 15cos 19 = 14.2 units.

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1 year ago

Add the polynomials: (-5 - 7x^2); (5 + 7x^3) *

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3 years ago

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2 years ago

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3 years ago

- What is the complete factorization of 4x2 – 24xy + 36y2 ?

Rzqust [24]

<u>Answer: </u>

The complete factorization of $4 x^{2}-24 x y+36 y^{2}$ are 4(x-3y)(x+3y)

<u>Solution:</u>

Given Data:

$4 x^{2}-24 x y+36 y^{2}$

Take common value in all the three term.so we take 4 as common term in the above expression

$4 x^{2}-24 x y+36 y^{2}=4\left(x^{2}-6 x y+9 y^{2}\right)$

Now factorize the expression $\left(x^{2}-6 x y+9 y^{2}\right)$

Find the two numbers, whose product should be 9 and sum should be -6.

-3,-3 are the numbers which satisfy the above condition.

When we add -3-3=Sum is 6

Product of -3 $\times$ -3= 9

-3 , -3 satisfies the condition.

So the expression will become as $x^{2}-6 x y+9 y^{2}$ = $x^{2}-3 x y-3 x y+9 y^{2}$

Take the common term

x(x-3y)+3y(x-3y)

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hence the complete factorization of $4 x^{2}-24 x y+36 y^{2}$ are 4(x-3y)(x+3y)

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3 years ago