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yaroslaw [1]
3 years ago
13

What are the lengths of the legs of a right triangle in which one acute angle measures 19° and the hypotenuse is 15 units long?

Mathematics
2 answers:
stich3 [128]3 years ago
8 0
The legs of a triangle with a hypotenuse that measures 15 units long have lengths that are equal to 15 times the sine or cosine of the given angle.
                      leg 1 = (15 units) x (cos 19) = 14.18 units
                      leg 2 = (15 units) x (sin 19) = 4.88 units
The lengths of the legs are 14.18 units and 4.88 units. 
Anarel [89]3 years ago
3 0
The side opposite the angle 19 degrees is given by 15sin 19 = 4.9 units, while the side adjacent the angle 19 degrees is given by 15cos 19 = 14.2 units.
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How do I answer this question?​
Novay_Z [31]

Due to the Triangle Angle Sum Theorem, we know that the sum of the interior angles of a triangle equals 180 degrees, therefore,

180 = m<1 + m<2 + m<3

180 - m<3 = m<1 + m<2

But, we also know that m<4 + m<3 = 180 degrees.

180 = m<3 + m<4

180 - m<3 = m<4

Both m<4 and m<1 + m<2  equals 180 - m<3

m<4 = m<1 + m<2

5 0
3 years ago
2.) If z varies inversely as r, and z= 24 when r = 6, find r when z= 12
Schach [20]

Step-by-step explanation:

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7 0
2 years ago
Create an equation that has a solution of 6.
PolarNik [594]
2x=12 is an equation with the solution of 6
5 0
3 years ago
What is the ratio a:b if 8a=3b?
Digiron [165]

The ratio a:b is 3:8

Step-by-step explanation:

In simple words, the ratio a:b means the fraction a/b.

So we will have to solve the given equation for a/b

Given

8a=3b

Dividing both sides by 8

\frac{8a}{8}=\frac{3b}{8}\\a=\frac{3b}{8}

Dividing both sides by b

\frac{a}{b}=\frac{3b}{8*b}\\\frac{a}{b} =\frac{3}{8}

The ratio a:b is 3:8

Keywords: Ratios, Fractions

Learn more about ratios at:

  • brainly.com/question/4694425
  • brainly.com/question/4695279

#LearnwithBrainly

5 0
3 years ago
In a class, 60% of the students are girls. There are 18 girls in the class.
N76 [4]

Answer:

The answer is 30

Step-by-step explanation:

If you were to do 50% of 30, it would be 15 students that are girls. There's 18 students that are girls though, so the extra 10% would make 18 students in the class girls. The remaining 40% would be 12 boys. So basically you're taking 10% from one side and putting it in the other because 50% of 30 is 15 (well this is at least how I would do it, I don't know how others would do it though)

5 0
2 years ago
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