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Answer:
The resistance of the wire after being heated is approximately 1.15 times the resistance before being heated.
Explanation:
The resistance of the wire goes up as the temperature goes up.
By Ohm's law, we have the relationship between the resistance of a conductor R, the current flowing through it, I, and the voltage across it, V,
As described, the current through the wire decreases so, to maintain the same voltage, the resistance must increase when the wire is heated. Let's say R1 is the resistance before heating the wire and R2 is the resistance after,
Let's solve for R2,
In this case, I1 = 0.3A and I2 = 0.26A,
Hence, the <u><em>resistance of the wire after being heated is approximately 1.15 times the resistance before being heated.</em></u>
Answer:
Explanation:
The moving charged particles in an electric current are called charge carriers. In metals, one or more electrons from each atom are loosely bound to the atom, and can move freely about within the metal. These conduction electrons are the charge carriers in metal conductors.
The flow of electrons in a direction is known as electric current. The tendency of attraction between the positive and negative charges makes electric current flow through a wire
Answer:
The change in the internal energy of the first system is 300 J
The second system will do zero work in order to have the same internal energy.
Explanation:
Given;
heat added to the first system, Q₁ = 500 J
heat added to the second system, Q₂ = 300 J
work done by the first system, W₁ = 200 J
The change in the internal energy of the system is given by the first law of thermodynamics;
ΔU = Q - W
where;
ΔU is the change in internal energy of the system
The change in the internal energy of the first system is calculated as;
ΔU₁ = Q₁ - W₁
ΔU₁ = 500 J - 200 J
ΔU₁ = = 300 J
The work done by the second system to have the same internal energy with the first.
ΔU₁ = Q₂ - W₂
W₂ = Q₂ - ΔU₁
W₂ = 300 J - 300 J
W₂ = 0
The second system will do zero work in order to have the same internal energy.
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Answer:
Experiments showed that increasing the light frequency increased the kinetic energy of the photoelectrons, and increasing the light amplitude increased the current.
Explanation:
The photocurrent increases linearly with the intensity of the incident light but is independent of its frequency. The stopping potential increases linearly with the frequency of the incident light but is independent of its intensity.