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3 years ago

13

PLEASE USE KINEMATIC EQUATIONS!!!

1 answer:

liberstina [14]3 years ago

5 0

The total time for car to travel the given distance is 2 s.

<h3>Time of motion of the car</h3>

The time of motion of the car is determined by applying second kinematic equation as shown below;

$s = vt + \frac{1}{2}at^2\\\\$

where;

v is the constant speed = 6m/s
t is the time of motion = ?
a is the acceleration = 1.5 m/s²
s is the distance traveled by the car = 15 m

Thus, the total time for car to travel the given distance is 2 s.

Learn more about time of motion here: brainly.com/question/2364404

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A bubble originating at the bottom of a lake rises to the surface within 10.0 seconds with an acceleration of 10.0 meters/second

Bad White [126]

I KNOW that you must have seen this formula before. It gives
the distance covered in a certain time of accelerated motion:

   D = 1/2 A T²

   Distance covered= (1/2) (Acceleration) (Time squared) .

The question gives us the acceleration and the time.
I've got a weird idea: Let's plug them into the formula. OK ?

   Distance = (1/2) (10 m/s²) (10 sec)²

   = (5 m/s²) (100 sec²)

   = 500 meters .

   Deep lake !

6 0

3 years ago

Why are networks of cables not used to send information from a remote

Alexxx [7]

Answer:

D-The information needs to travel only a short distance.

Explanation:

5 0

3 years ago

Read 2 more answers

I WILL GIVE BRAINLIST just please help with these problems 3

statuscvo [17]

Answer:

16. 68.18 Km/h

17. 3 miles.

Explanation:

16. Determination of the speed

Distance travelled = 150 Km

Time = 2.2 hours

Speed =?

Speed is simply defined as the distance travelled with time. Mathematically, it is expressed as:

Speed = Distance / time

With the above formula, we can obtain the speed as follow:

Distance travelled = 150 Km

Time = 2.2 hours

Speed =?

Speed = Distance /time

Speed = 150 / 2.2

Speed = 68.18 Km/h

17. Determination of the distance.

Speed = 3 mph

Time = 1 hour

Distance =?

Speed = Distance /time

3 = distance / 1

Distance = 3 miles

3 0

3 years ago

A speed skater just finished a race. After she crossed the finish line, she coasted to a complete stop. If her initial speed was

romanna [79]

Answer:

5seconds

Explanation:

because she was going through the same time

6 0

2 years ago

A plane flies 446 km east from city A to city B in 43.0 min and then 939 km south from city B to city C in 1.10 h. For the total

NeTakaya

Answer:

(a) Magnitude is 1039 km

(b) Direction of the displacement is $64.59^{\circ}$ South of East

(c) Average velocity magnitude is 570.88 km

(d) The direction of average velocity is $64.59^{\circ}$ South of East

(e) Average speed is 759.34 km/h

Solution:

Distance moved from A to B in East direction, $\vec{AB} = 446 km$

Distance moved from B to C in South direction, $\vec{BC} = - 939 km$

Time taken to move from A to B, t = 43.0 min = 0.72 h

Time taken to move from B to C, t' = 1.10 h

Now,

(a) The magnitude of displacement of the plane is provided by AC as shown in fig 1 and can be given as:

$AC = \sqrt{(AB)^{2} + (BC)^{2}}$

$AC = \sqrt{(446)^{2} + (- 939)^{2}}$ = 1039 km

(b) Direction of the displacement is given by:

$tan\theta = \frac{\vec{BC}}{\vec{AB}}$

$\theta = tan^{- 1}(\frac{- 939}{\vec{446}}) = - 64.59^{\circ}$

$64.59^{\circ}$ South of East

(c) Magnitude of the average speed is given by:

$v_{avg} = \frac{AC}{t + t'}$

$v_{avg} = \frac{1039}{1.82} = 570.88 km/h$

(d) The direction of the average velocity is the same as that of the displacement, i.e., $64.59^{\circ}$ South of East.

(e) The average speed of the [plane is given by:

$v'_{avg} = \frac{Total\ Distance\ Traveled}{Total\ Time}$

$v'_{avg} = \frac{446 + 939}{1.10 + 0.72} = 759.34 km/h$

6 0

3 years ago