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2 years ago

Mr foster and his students have launched a small rocket. The rocket has just started moving upward due to the thrust

Physics

1 answer:

leva [86]2 years ago

4 0

The thrust force that cause the small rocket can be defined as a push, Thrust is a force or a push.

From Newton's First Law

Newton's first law can be stated as:

A body will continue ti be arrest or uniform motion except acted upon by an external force

If an object, such as the rocket, is at rest then the forces on it are balanced. It takes an additional force to unbalance the forces and make the object move. If the object is already moving, it takes such an unbalanced force, to stop it, change its direction from a straight line path, or alter its speed.

Newton's Second Law

This law of motion is essentially a statement of a mathematical equation. The three parts of the equation are

Mass (m)

Acceleration (a), and

force (f)

Using letters to symbolise each part, the equation can be written as follows:

Learn more at :

brainly.com/question/20337199

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3 years ago

Two blocks A and B have a weight of 11 lb and 5 lb , respectively. They are resting on the incline for which the coefficients of

Alchen [17]

Answer:

$\theta=10.20^{\circ}$

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Explanation:

First of all, we analyze the system of blocks before starting to move.

$\Sum F_{x}=P_{A}sin(\theta)+P_{B}sin(\theta)-F_{fA}-F_{fB}=0$

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$11sin(\theta)+5sin(\theta)-0.16*11cos(\theta)-0.23*5cos(\theta)=0$

$16sin(\theta)-2.91cos(\theta)=0$

$tan(\theta)=0.18$

$\theta=arctan(0.18)$

$\theta=10.20^{\circ}$

Hence, the incline angle θ for which both blocks begin to slide is 10.20°.

Now, if we do a free body diagram of block A we have that after the block moves, the spring force must be taken into account.

$P_{A}sin(\theta)-F_{fA}-F_{spring}=0$

Where:

$F_{spring} = k\Delta l=2.1\Delta l$

$P_{A}sin(\theta)-0.16*11cos(\theta)-2.1\Delta l=0$

$\Delta l=\frac{11sin(\theta)-0.16*11cos(\theta)}{2.1}$

$\Delta l=0.10 ft$

Therefore, the required stretch or compression in the connecting spring is 0.10 ft.

I hope it helps you!

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