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3 years ago

Please help is for today!

Mathematics

1 answer:

horsena [70]3 years ago

4 0

Answer:

Given :

Cost of onsite repair = 3 times cost of at store

cost of mai services = cost of at store -10

On-site work completed last week = 15

At store work completed = 40

mail work completed = 5

Let's Assume :

The cost of at store = x

the cost of in-site = 3x

the cost of mail service = x-10

Solution :

Part 1] :

See the "let's Assume" part

The cost of at store = x

the cost of in-site = 3x

the cost of mail service = x-10

Part 2 ]

The equation that can be formed is :

15(3x)+40(x)+5(x-10) = 2650 ,

or, 45x+40x+5x-50 = 2650

or, 90x = 2700

Part 3]

To determine the cost of on-site work, we will solve the equation formed in "Part 2"

So, 90x = 2700

or, 9x = 270

or, x = 270/9

or, x = 30

So,

The cost of on site repair = ₹90

The cost of at store = 30

The cost of by mail service = 20

Hope it helped Freind !

Step-by-step explanation:

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geniusboy [140]

Answer:

Step-by-step explanation:

(1)

a1=-2

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3 years ago

Which values of k are solutions to the inequality StartAbsoluteValue negative k minus 2 EndAbsoluteValue less-than 18? Check all

Stella [2.4K]

Answer:

You could just replace all the given possible values of k in the inequality and see which ones are solutions, but let's solve this in a more interesting way:

First, remember how the absolute value works:

IxI = x if x ≥ 0

IxI = -x if x ≤ 0

Then if we have something like:

IxI < B

We can rewrite this as

-B < x < B

Now let's answer the question, here we have the inequality:

I-k -2I < 18

Then we can rewrite this as:

-18 < (-k - 2) < 18

Now let's isolate k: