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alexandr402 [8]
3 years ago
8

Every _____ tessellates. A. Decagon B. Polygon C. Triangle D. Hexagon

Mathematics
1 answer:
olga2289 [7]3 years ago
8 0
The answer is letter B. Every polygon tesselates. Since the word 'tesselate' here means a pattern of shapes put together without any gaps, then I think every polygon tesselates if they are put side by side together in varying amounts and leave absolutely no gaps or spaces between each other.
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Reese wants to organize a party and decides to save money for it.He calculates that he needs $420 in 9 weeks.He already has $60
disa [49]

Answer:

3840

Step-by-step explanation:

5 0
2 years ago
Find the 7th term of the sequence
NikAS [45]

Answer:

3rd option, 4096

Step-by-step explanation:

4⁰ = 1, 1st term

4¹ = 4, 2nd term

4² = 16, 3rd term

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4⁶ = 4096, 7th term

Answered by GAUTHMATH

8 0
3 years ago
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Vanyuwa [196]

I'm not sure if this dividing,multiplying,subtracting or adding but for adding i got 6 as my answer.I don't know if this the correct answer but its better than having no answer right?

3 0
3 years ago
Read 2 more answers
A=zm+z solve for m please help!!!!!
Svetach [21]

Answer:

(a-z)/z = m

Step-by-step explanation:

a = zm+z

Subtract z from each side

a-z = mz+z-z

a-z = mz

Divide by z

(a-z) /z = mz/z

(a-z)/z = m

5 0
3 years ago
Suppose that p is the probability that a randomly selected person is left handed. The value (1-p) is the probability that the pe
solmaris [256]

Answer:

a) 1/2

b) 250

Step-by-step explanation:

The start of the question doesn't matter entirely, although is interesting to read. What we are trying to do is find the value for p such that 1000p(1-p) is maximized. Once we have that p, we can easily find the answer to part b.

Finding the value that maximizes 1000p(1-p) is the same as finding the value that maximizes p(1-p), just on a smaller scale. So, we really want to maximize p(1-p). To do this, we will do a trick called completing the square.

p(1-p)=p-p^2=-p^2+p=-(p^2-p)=-(p^2-p+1/4)-(-1/4)=-(p-1/2)^2+1/4.

Because there is a negative sign in front of the big squared term, combined with the fact that a square is always positive, means we need to find the value of p such that the inner part of the square term is equal to 0.

p-1/2=0\\p=1/2.

So, the answer to part a is \boxed{1/2}.

We can then plug 1/2 into the equation for p to find the answer to part b.

1000(1/2)(1-1/2)=1000(1/2)(1/2)=1000*1/4=250.

So, the answer to part b is \boxed{250}.

And we're done!

3 0
2 years ago
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