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3 years ago

A man invests 10000 for 3 years at a certain rate of interest, compounded annually. At the

Mathematics

2 answers:

Rufina [12.5K]3 years ago

4 0

Step-by-step explanation:

(I) Principle = Rs 10000, After 1 year amount

= Rs 11200 so interest after 1 year

= Rs 1200

R = 12%

Amount = P(1+R/100)T

11200 = 10000(1+R/100)1

R = 12%——————————————————————————————————————

(Ii)Interest for second year = 11200(1+12/100)1 - 11200 = Rs 1344

(iii)Amount after 3 year = 10000(1+12/100)3 = Rs 14049.28

Natali [406]3 years ago

3 0

Step-by-step explanation:

10000, After 1 year amount = 11200 so interest after 1 year = 1200

Amount = P(1+R/100)T

11200 = 10000(1+R/100)1

R = 12%

Interest for the second year = 11200(1+12/100)1 - 11200 = 1344

after 3 years = 10000(1+12/100)3 = 14049.28

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