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Wittaler [7]
3 years ago
12

A man invests 10000 for 3 years at a certain rate of interest, compounded annually. At the

Mathematics
2 answers:
Rufina [12.5K]3 years ago
4 0

Step-by-step explanation:

(I) Principle = Rs 10000, After 1 year amount

= Rs 11200 so interest after 1 year

= Rs 1200

R = 12%

Amount = P(1+R/100)T

11200 = 10000(1+R/100)1

R = 12%——————————————————————————————————————

(Ii)Interest for second year = 11200(1+12/100)1 - 11200 = Rs 1344

(iii)Amount after 3 year = 10000(1+12/100)3 = Rs 14049.28

Natali [406]3 years ago
3 0

Step-by-step explanation:

10000, After 1 year amount = 11200 so interest after 1 year = 1200

Amount = P(1+R/100)T

11200 = 10000(1+R/100)1

R = 12%

Interest for the second year = 11200(1+12/100)1 - 11200 = 1344

after 3 years = 10000(1+12/100)3 = 14049.28

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Answer:

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Step-by-step explanation:

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The number of arrangements of n elements is given by:

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Arrangements of n elements, divided into groups:

The number of arrangements of n elements, divided into groups of n_1, n_2,...,n_n elements is given by:

A_{n}^{n_1,n_2,...,n_n} = \frac{n!}{n_1!n_2!...n_n!}

In this case:

9 pens, into groups of 5, 3 and 1. So

A_{9}^{5,3,1} = \frac{9!}{5!3!1!} = 504

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3 years ago
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Answer:

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7 0
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I dont really understand this. ranking brainliest !
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Step-by-step explanation:

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