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2 years ago

A man invests 10000 for 3 years at a certain rate of interest, compounded annually. At the

Mathematics

2 answers:

Rufina [12.5K]2 years ago

4 0

Step-by-step explanation:

(I) Principle = Rs 10000, After 1 year amount

= Rs 11200 so interest after 1 year

= Rs 1200

R = 12%

Amount = P(1+R/100)T

11200 = 10000(1+R/100)1

R = 12%——————————————————————————————————————

(Ii)Interest for second year = 11200(1+12/100)1 - 11200 = Rs 1344

(iii)Amount after 3 year = 10000(1+12/100)3 = Rs 14049.28

Natali [406]2 years ago

3 0

Step-by-step explanation:

10000, After 1 year amount = 11200 so interest after 1 year = 1200

Amount = P(1+R/100)T

11200 = 10000(1+R/100)1

R = 12%

Interest for the second year = 11200(1+12/100)1 - 11200 = 1344

after 3 years = 10000(1+12/100)3 = 14049.28

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In an equation what do v1 and v2 represent

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If this is regards to science and take off then V1= Takeoff decision speed.
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2 years ago

The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. The follow

kipiarov [429]

Answer:

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

Step-by-step explanation:

The average undergraduate cost for tuition, fees, and room and board for two-year institutions last year was $13,252. Test if the mean cost has increased.

At the null hypothesis, we test if the mean cost is still the same, that is:

$H_0: \mu = 13252$

At the alternative hypothesis, we test if the mean cost has increased, that is:

$H_1: \mu > 13252$

The test statistic is:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.

13252 is tested at the null hypothesis:

This means that $\mu = 13252$

The following year, a random sample of 20 two-year institutions had a mean of $15,560 and a standard deviation of $3500.

This means that $n = 20, X = 15560, s = 3500$

Value of the test statistic:

$t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}$

$t = \frac{15560 - 13252}{\frac{3500}{\sqrt{20}}}$

$t = 2.95$

P-value of the test and decision:

The p-value of the test is found using a t-score calculator, with a right-tailed test, with 20-1 = 19 degrees of freedom and t = 2.95. Thus, the p-value of the test is 0.0041.

The p-value of the test is 0.0041 < 0.05, which means that there is sufficient evidence at the 0.05 significance level to conclude that the mean cost has increased.

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2 years ago

If 3 times a number is decreased by 12, the result is 5

Nadusha1986 [10]

3 times a # (# isn't specified, so you should use a variable): 3x
result is 5: =5
Put it all together: 3x=5

6 0

2 years ago

Please help me asap ty :)

Art [367]

Answer:

y = 5x+7

Step-by-step explanation:

Parallel lines have the same slope so y = 5x+9 is in slope intercept form

y = mx+b where m is the slope and b is the y intercept

The slope is 5

The new line will have a slope of 5

y = 5x+b

We know a point on the line (-2,-3)

Substitute this point into the equation

-3 = 5(-2)+b

-3 = -10+b

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7 = b

y = 5x+7

3 0

1 year ago

Read 2 more answers

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geniusboy [140]

Answer:

$x=144$

Step-by-step explanation:

Therefore, $x=144$ should be your final answer.

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2 years ago