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kenny6666 [7]
3 years ago
5

Which graph represents a quadratic function with a vertex at (0, 0)

Mathematics
1 answer:
____ [38]3 years ago
5 0

PARABOLA

On a coordinate plane, a parabola opens up. It goes through (negative 5, 6), has a vertex of (0, 0), and goes through (5, 6).

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Fiesta28 [93]

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I'm not sure if this is what your looking for but the answer should be √11

Step-by-step explanation:

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Is 7/8 greater than or less than 1/2
shutvik [7]
Greater than. 1/2 is only 4/8
6 0
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Ada buys 3 pounds 8 ounces of ham and 4 pounds 2 ounces of cheese for a party. How much ham and did she buy ?
Lesechka [4]
C) 7 pounds 10 ounces 7 5/8

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3 years ago
determine the slope of the tangent to the curve at the point y=(3x)(sinx) at the point with x-coordinate pi/2 ​
damaskus [11]

Answer:

Step-by-step explanation:

The slope of the tangent to a curve is the derivative of the curve. We need to find the derivative of the function and then evaluate the derivative at that given x value. The derivative is found using the product rule:

y'=f(x)g'(x)+f'(x)g(x)

Let's call 3x our f(x) and sin(x) our g(x). Filling in the formula for the derivative using the product rule looks like this:

y'=3x(cosx)+3sinx

That gives us the derivative, which is the slope formula that can be used at ANY x value anywhere on the curve to find the slope of the line tangent to the curve at that x value. If we want to find the slope of the tangent line to the curve at x = pi/2, we evaluate the slope formula at x = pi/2 (remember that y' is the same exact thing as the slope):

y'(slope)=3(\frac{\pi}{2})(cos\frac{\pi}{2})+3(sin\frac{\pi}{2})

From the unit circle (or experience, since you're in advaced math), we know that the cosine of pi/2 is 0 and that the sin of pi/2 = 1:

y'(slope)=3(\frac{\pi}{2})(0)+3(1) simplifies to

y' (slope) = 3

That means that the slope of the line tangent to the curve at the point x = pi/2 is 3.

8 0
4 years ago
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Over [174]

Answer:

255.8

Step-by-step explanation:

first

1/6*1535

=255.8

5 0
4 years ago
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