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rusak2 [61]
3 years ago
12

A retired math teacher takes his grandson shopping. He tells his grandson that they can spend x

Mathematics
1 answer:
leva [86]3 years ago
4 0

Answer:

Addition, 83.6

Step-by-step explanation:

x - 72.6 = 11, x = 83.6

The grandson must add 72.6 to both sides to solve for x.

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Here is the question
serg [7]

First find the amount of the difference between the original price and the current price:


$10,600 - $7,400 = $3,200


Divide the difference by the original price:

3200 / 7400 = 0.4324 = 43.2% increase.


5 0
3 years ago
There are 60 apples and then add 59 apples two times . How many apples and there altogether
STALIN [3.7K]

Answer:

Step-by-step explanation:

59 apples two times = 59 x 2 = 118 apples

Total apples = 118 + 60 = 178 apples

7 0
3 years ago
Y=3x+6 complete with the table
Mama L [17]

Answer:

y=3,6,9,12,15

Step-by-step explanation:

Y=3x+6

y=3(-1)+6

y=3

y=3(0)+6

y=6

y=3(1)+6

y=9

y=3(2)+6

y=12

y=3(3)+6

y=15

3 0
2 years ago
Read 2 more answers
WILL MARK BRANLIEST 50 POINTS PLEASE HELP ( CORRECT ANSWER )<br><br> Simplify. 30k2 + 6k 5k + k
Vera_Pavlovna [14]
Simplified answer would be 60k^2+k

and you get that answer by combining like terms, Good Luck! 

8 0
3 years ago
Read 2 more answers
A Packaging Company produces boxes out of cardboard and has a specified weight of 16 oz. A random sample of 36 boxes yielded a s
user100 [1]

Answer:

The margin of error is of 0.73 oz.

The 99% confidence interval for the true mean weight of the boxes is between 14.57 oz and 16.03 oz. This means that we are 99% sure that the true mean weight of all boxed produced by the Packaging Company is between these two values, and that the specified weight is in this interval.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.99}{2} = 0.005

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.005 = 0.995, so Z = 2.575.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 2.575\frac{1.7}{\sqrt{36}} = 0.73

The margin of error is of 0.73 oz.

The lower end of the interval is the sample mean subtracted by M. So it is 15.3 - 0.73 = 14.57 oz.

The upper end of the interval is the sample mean added to M. So it is 15.3 + 0.73 = 16.03 oz.

The 99% confidence interval for the true mean weight of the boxes is between 14.57 oz and 16.03 oz. This means that we are 99% sure that the true mean weight of all boxed produced by the Packaging Company is between these two values, and that the specified weight is in this interval.

4 0
2 years ago
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