Answer:
x=-5-2yi/3+4i
y=3xi/2+6+15i/2
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
120 divided by 4 is 30. 30 cars are filled in the spaces.
angle1 = 4y - 9°
angle2 = 40°
angle3 = 5y°
Angle sum property
180° = angle1 + angle2 + angle3
Therefore,
180 = (4y - 9) + 40 + 5y
180 = 4y - 9 + 40 + 5y
180 = 9y + 31
180 - 31 = 9y
149 = 9y
149/9 = y
I hope that this helps:
0.65+1.2=1.85
1.85*365=675.25
answer:675.25
Answer:
Sean's rocket lands 3 seconds after Kiara's rocket.
Step-by-step explanation:
Kiara: f(t)= -16t² + 80t
Sean: h(t) = -16t² + 120t + 64
Assume that both rockets launch at the same time. We need to be suspicious of Sean's rocket launch. His equation for height has "+64" at the end, whereas Kiara's has no such term. The +64 is the starting height iof Sean's rocket. So Kiara has a 64 foot disadvantage from the start. But if it is a race to the ground, then the 64 feet may be a disadvantage. [Turn the rocket upside down, in that case. :) ]
We want the time, t, at which f(t) and h(t) are both equal to 0 (ground). So we can set both equation to 0 and calculate t:
Kiara: f(t)= -16t² + 80t
0 = -16t² + 80t
Use the quadratic equation or solve by factoring. I'll factor:
0 = -16t(t - 5)
T can either be 0 or 5
We'll choose 5. Kiara's rocket lands in 5 seconds.
Sean: h(t) = -16t² + 120t + 64
0= -16t² + 120t + 64
We can also factor this equation (or solve with the quadratic equation):
0 = -8(t-8)(2t+1)
T can be 8 or -(1/2) seconds. We'll use 8 seconds. Sean's rocket lands in 8 seconds.
Sean's rocket lands 3 seconds after Kiara's rocket.
