The answer is Hardware level works upon dynamic parallelism whereas, the software level works on static parallelism. Dynamic parallelism means the processor decides at run time which instructions to execute in parallel,
Answer:
False.
Explanation:
The /tmp directory is a directory that contains files that are required temporarily and also for temporary storage of data.The data inside the /tmp directory gets deleted when the system boots or shuts down.Since the directory exists permanently the content inside it is temporary.
So we can conclude that the answer is False.
Answer:
c. You cannot change the name, return type, or parameters of a method defined by the interface.
Explanation:
When implementing an interface:
- The return type of the implementing method should be same as the one defined in the interface.
- The parameters of the implementing method should be the same as defined in the interface.
- The name of the method should be the same as that defined in the interface.
So among the given options , option c is the most relevant as it captures all the above conditions.
Answer:
SuperFetch
Explanation:
Superfetch is a memory management technique on windows service that enables or fetch frequently use applications on systems and launch them faster because the frequently use applications has been preload into the system memory for easy access when they want to be used.
SuperFetch always takes notice of all application running on your system in which when you exit a frequently used application SuperFetch will preload them immediately since it is saved on the system memory.
One of the most important part of Superfetch is that it saves alot of time because you don't have to search the applications before you get access to them in as far as the application was frequently used.
import java.util.Scanner;
public class MyClass1 {
public static void main(String args[]) {
Scanner scan = new Scanner(System.in);
int smallest = 0, largest = 0, num, count = 0;
while (true){
System.out.println("Enter a number (-1 to quit): ");
num = scan.nextInt();
if (num == -1){
System.exit(0);
}
else if (num < 0){
System.out.println("Please enter a positive number!");
}
else{
if (num > largest){
largest = num;
}
if (num < smallest || count == 0){
smallest = num;
count++;
}
System.out.println("Smallest # so far: "+smallest);
System.out.println("Largest # so far: "+largest);
}
}
}
}
I hope this helps! If you have any other questions, I'll do my best to answer them.
