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bearhunter [10]
3 years ago
14

A coin is slightly bent, and as a result the probability of a head is 0.52. Suppose that you toss the coin four times. Use the B

inomial formula to find the probability of 3 or more heads
Mathematics
1 answer:
Nataly_w [17]3 years ago
5 0
Hi <span>Spor7tdardLamilokab, this particular equation is a binomial probability equation:

P(X) = </span>( \frac{n}{k}) * p^{k} *(1 - p)^{n-k}

Note that it's not n / k, but rather the notation is n choose k. Brainly software will not allow me to do this, but imagine the n choose k, without the bar, and that the correct notation.
 
Where (\frac{n}{k}) equals  \frac{n!}{k!(n-k)!} , where n! is n * (n-1) * (n-2) 8 ... 1

So for your particular equation:

P(x \geq 3) =  (\frac{5}{3}) * 0.52^{3} * (1 - .52)^{5-3}

You would repeat the above equation for 4 as well and add that to the computation for 3, since you want the probability that you'll get 3 or more heads.

Solving this produces the answer:

P(x\geq 3) = 0.34308352

You can also solve this with a TI 83 or 84.

To do this, the steps are 2ND | VARS (or DISTR) | BINOMPDF| TRIALS | PROBABILITY | X VALUE

Doing this for 3 and 4 produces the same result:

binompdf(4, 0.52, 3) + binompdf(4, 0.52, 4) = 0.34308352


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