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3 years ago

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The binomial (a+5) is a factor of a2+7a+10. What is the other factor? (a+2) (a+5) (a−2) (a−5)The binomial (y − 2) is a factor of

y2 − 10y + 16. What is the other factor? (y − 5) (y + 5) (y − 8) (y + 8)

1 answer:

Dominik [7]3 years ago

8 0

Step-by-step explanation:

a^2 +7a + 10 = a(a+2) +5(a+2) = (a+5)(a+2)

y^2 -10y +16=y(y-2) -8(y-2) =(y-8)(y-2)

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A thin tube stretched across a street counts the number of pairs of wheels that pass over it. A vehicle classified as type A wit

aliina [53]

Answer: All possible solutions would be

(1,41), (8,33), (15,25), (22,17), (29,9), (36,1)

Step-by-step explanation:

Let the number of vehicle of type A be 'x'.

Let the number of vehicle of type B be 'y'.

Since we have given that

Number of axles of type A = 2

Number of axles of type B = 9

After 2 hours, number of counts = 101

so, our equation becomes,

$2x+9y=101$

So, all possible solutions would be

(1,41), (8,33), (15,25), (22,17), (29,9), (36,1)

7 0

2 years ago

When Natalie finishes drawing the large triangle on the poster board, what will be the approximate measure of side BC? Round to

gtnhenbr [62]

Answer:

31 cm

Step-by-step explanation:

The complete question is attached.

A triangle is a polygon with three sides (three edges and three vertices). There are different types of triangles which are equilateral triangles, right triangles, scalene triangles, obtuse triangles, acute triangles, and isosceles triangles.

An equilateral triangle is a triangle in which all its sides are equal and all its angles are equal to 60°.

From the triangle, AB = BC = AC = 9.5 cm

Since the triangle is enlarged 3.25 times, hence:

new length of BC = 9.25 cm × 3.25 = 30.875

New length of BC = 31 cm to nearest cm

7 0

3 years ago

Hihi , please help if able.

earnstyle [38]

Answer:

27

Step-by-step explanation:

3².2³/2² + 3².2²/2² = 27

7 0

3 years ago

Read 2 more answers

Can someone solve this?

ladessa [460]

First question:

Recall that $\cos^2x+\sin^2x=1$ and $\sqrt{x^2}=|x|$ for all $x$ . So

$\sqrt{1-\cos^2x}=\sqrt{\sin^2x}=|\sin x|$

$\sqrt{1-\sin^2x}=\sqrt{\cos^2x}=|\cos x|$

For $0$ , we expect both $\cos x>0$ and $\sin x>0$ (i.e. the sine and cosine of any angle that lies in the first quadrant must be positive). By definition of absolute value, $|x|=x$ if $x>0$ .

So we have

$\dfrac{\sqrt{1-\cos^2x}}{\sin x}+\dfrac{\sqrt{1-\sin^2x}}{\cos x}=\dfrac{\sin x}{\sin x}+\dfrac{\cos x}{\cos x}=1+1=\boxed{2}$

making H the answer.

Second question:

C is always true, because the inequality reduces to x > y.

6 0

3 years ago

Write a word problem for this equation.<br> 10 lb - w = 3 lb

Luden [163]

Answer:

10 people buy slushies and the price of each is lb. They have already spent w on food. How much did they spend on slushies.

Step-by-step explanation:

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3 years ago