Answer:
(a) Barium is produced at the negative electrode
(b) Iodine is produced at the positive electrode
Explanation:
When an electric current is passed through a solution containing electrolyte, a non spontaneous reaction is stimulated. This results in the flow of <u>positively charged ions to negatively charged electrodes(</u><u>cathode</u><u>) and negatively charged ions to positively charged electrodes(</u><u>anode</u><u>)</u>
When an electric current is passed through molten
in the electrolytic cell, the following reactions takes place:
→
+ 2
At the anode;
Iodine ions will lose an electron and will be oxidized to iodine
→
+ 
At the cathode;
Barium ions gains electrons and its reduced to barium metal
+
→ Ba
Answer:
Current, I = 8 A
Explanation:
We have,
Voltage, V = 160 V
Resistance, R = 20 ohms
It is required to find the current. The relation between current, voltage and resistance is called Ohm's law. It is given as :

I = current

So, the value of current is 8 A.
We can use the ideal gas law equation to find the volume occupied by oxygen gas
PV = nRT
where ;
P - pressure - 52.7 kPa
V - volume
n - number of oxygen moles - 12.0 g / 32 g/mol = 0.375 mol
R - universal gas constant - 8.314 Jmol⁻¹K⁻¹
T - temperature - 25 °C + 273 = 298 K
substituting the values in the equation
52 700 Pa x V = 0.375 mol x 8.314 Jmol⁻¹K⁻¹ x 298 K
V = 17.6 L
volume of the gas is 17.6 L
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Answer:
34.02 g.
Explanation:
Hello!
In this case, since the gas behaves ideally, we can use the following equation to compute the moles at the specified conditions:

Now, since the molar mass of a compound is computed by dividing the mass over mass, we obtain the following molar mass:

So probably, the gas may be H₂S.
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