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marin [14]
3 years ago
9

Explain how hydrogen bonding contributes to water's high heat of vaporization

Chemistry
1 answer:
pashok25 [27]3 years ago
4 0

The heat/enthalpy of vaporization of water represents the energy input required to convert one mole of water into vapor at a constant temperature. Intermolecular forces including hydrogen bondings of significant strength hold water molecules in place under its liquid state. Whereas the molecules experience almost no intermolecular interactions under the gaseous state- consider the way noble gases molecules interact. It is thus necessary to supply sufficient energy to overcome all intermolecular interactions present in the substance under its liquid state to convert the substance into a gas. The heat of vaporization is thus related to the strength of the intermolecular interactions.

Water molecules contain hydrogen atoms bonded directly to oxygen atoms. Oxygen atoms are highly electronegative and take major control of electrons in hydrogen-oxygen bonds. Hydrogen atoms in water molecules thus experience a strong partial-positive charge and would attract lone pairs of electron on neighboring water molecules. "Hydrogen bonds" refer to the attraction between hydrogen atoms bonded to electronegative elements and lone pairs of electrons. The hydrogen-oxygen bonds in water molecules are so polarized that hydrogen bonds in water are stronger than both dipole-dipole interactions and London Dispersion Forces in most other molecules. It thus take high amounts of energy to separate water molecules sufficiently apart such that they no longer experience intermolecular interactions and behave collectively like a gas. As a result, water has one of the highest heat of vaporization among covalent molecules of similar sizes.

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Sodium metal reacts with chlorine gas to produce sodium chloride. What mass (grams) of sodium metal would be needed to fully rea
gulaghasi [49]

Answer:

105.8 g of Na would be required

Explanation:

Let's think the reaction:

2Na(s)  + Cl₂(g)  →  2NaCl (s)

1 mol of chlorine reacts with 2 moles of sodium

Then, 2.3 moles of Cl₂ would react with (2.3 .2) / 1 = 4.6 moles

Let's determine the mass of them.

4.6 mol . 23 g/mol = 105.8 g

3 0
3 years ago
What is the volume of 0.80 grams of O2 gas at STP? (5 points) Group of answer choices 0.59 liters 0.56 liters 0.50 liters 0.47 l
Anarel [89]

Answer:

0.56 liters

Explanation:

First we <u>convert 0.80 grams of O₂ into moles</u>, using its molar mass:

  • 0.80 g ÷ 32 g/mol = 0.025 mol

At STP, 1 mol of any given mass occupies 22.4 L. With that information in mind we <u>calculate the volume that 0.025 moles of O₂ gas would occupy</u>:

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Thus the answer is 0.56 liters.

3 0
2 years ago
Express each of the following answers in the IUPAC format. Do not include any capitals or spaces in your name. Separate multiple
lorasvet [3.4K]

The full question is shown in the image attached

Answer:

See explanation

Explanation:

In naming an alkane, the first thing we do is to obtain the parent chain by counting the number of carbon atoms in the chain.

When we obtain that, then we identify the substituents and number them in such a way that they have the lowest numbers. The compounds shown have the following names according to the order in which the structures appear in the image attached;

1. 2-methyl propane

2. 2,4-dimethyl heptane

3. 2,2,3,3-tetramethyl butane

4. 5-ethyl-2,4-dimethyl octane

5 0
3 years ago
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NH4+ and NH3 are an acid-conjugate base pair, since NH4+ is an acid, while NH3 is its conjugate base (since it is without the H+).
H2O and H3O+ can also be considered an acid-conjugate base pair, since H3O+ is an acid, while H2O would be its conjugate base. (But if only 1 answer is to be selected, it should be the NH4+ and NH3)
NH4+ and H3O+ are both acids, and both H2O and NH3 can be considered bases.
4 0
3 years ago
Read 2 more answers
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Rudiy27
4.25mm / 137pm = 31 021 897.8
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