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4 years ago

Which of the following elements would you expect to have the highest ionization energy value, and why?

Chemistry

2 answers:

Alik [6]4 years ago

7 0

Neon, Ne, would have the highest ionization energy because it has a high effective nuclear charge and small radius.

Whitepunk [10]4 years ago

4 0

Answer:

D. Neon (Ne), because it has a high effective nuclear charge and small radius

Explanation:

Ionization energy is the amount of energy required to remove an electron from the valence orbital.

Chlorine (Cl) and fluorine (F) are halogens which have a general valence configuration of ns²np⁵ and are highly electronegative

Lithium (Li) is an alkali metal with a valence configuration of ns¹ and has a tendency to lose electrons readily

Neon (Ne) is a noble gas with a valence configuration of ns²np⁶. Here the outer shells have a complete octet and stable configuration which makes it difficult to remove electrons. In addition the high nuclear charge and small radius of Ne results in a strong force of attraction between the nucleus and the valence electrons. Therefore, Ne would have the highest ionization energy value.

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The following pairs of soluble solutions can be mixed. In some cases, this leads to the formation of an insoluble precipitate. D

Westkost [7]

Answer:

a) $K_{2} S$ and $NH_{4} Cl$ :

There are no insoluble precipitate forms.

b) $Ca Cl_{2}$ and $(NH_{4} )_{2} Co_{3}$ :

There are the insoluble precipitates of $CaCo_{3}$ forms.

c) $Li_{2}S$ and $MnBr_{2}$ :

There are the insoluble precipitates of $MnS$ forms.

d) $Ba(No_{3} )_{2}$ and $Ag_{2} So_{4}$ :

As $Ag_{2} So_{4}$ is insoluble, therefore no precipitate forms.

e) $Rb_{2}Co_{3}$ and $NaCl$ :

There are no insoluble precipitates forms.

Explanation:

Solubility rule suggests:- $K_{2} S$ ⇒ soluble, $NH_{4} Cl$ ⇒ soluble.

KCl ⇒ soluble, $(NH_{4})_{2} S$ ⇒ soluble.

There are no insoluble precipitate forms.

Solubility rule suggests:- $Ca Cl_{2}$ ⇒ soluble, $(NH_{4} )_{2} Co_{3}$ ⇒ soluble.

$CaCo_{3}$ ⇒ insoluble, $NH_{4} Cl$ ⇒ soluble.

There are the insoluble precipitates of $CaCo_{3}$ forms.

Solubility rule suggests:- $Li_{2}S$ ⇒ soluble, $MnBr_{2}$ ⇒ soluble.

$LiBr$ ⇒ soluble, $MnS$ ⇒ insoluble.

There are the insoluble precipitates of $MnS$ forms.

Solubility rule suggests:- $Ba(No_{3} )_{2}$ ⇒ soluble, $Ag_{2} So_{4}$ ⇒insoluble.

As $Ag_{2} So_{4}$ is insoluble, therefore no precipitate forms.

Solubility rule suggests:- $Rb_{2}Co_{3}$ ⇒ soluble, $NaCl$ ⇒ soluble.

$RbCl$ ⇒ soluble, $Na_{2} Co_{3}$ ⇒ soluble.

There are no insoluble precipitates forms.

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Objects 1 and 2 collide and stick together. Which best describes the momentum of the resulting single object? It is less than th

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Answer:

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Explanation:

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3 years ago

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