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2 years ago

6

Jimmy recently bought a car. It originally cost $28,000.00 and he received a

1 answer:

Sloan [31]2 years ago

8 0

Answer:

none of the given answers make sense, the answer would be 4,200

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Find an angle between 0 degrees and 360 degrees that is coterminal with 950 degrees

QveST [7]

Answer:

40 degrees

Step-by-step explanation:

(to find coterminal angles to a given angle, we add 360 degrees to the given angle or subject 360 degrees from the given angle any angle any number of time).

-1400 degrees is negative angl, so to get the coterminal angle between 0 degrees and 360 degrees ( the smallest positive coterminal angle), we must add multiples of 360 degrees until we get a possitive coterminal angle:

-1400 degrees+(360 degrees*4)

=-1400 degrees+1440

=40 degrees

so the answer is 40 degrees

5 0

2 years ago

What is the answer to 3/2000 as a percent

Nina [5.8K]

The answer to this is .15%

6 0

2 years ago

Read 2 more answers

Evaluate the following -5+4-3-6+9-3

Amanda [17]

Answer:

-4

Step-by-step explanation:

-5+4= -1

-1-3= -4

-4-6= -10

-10+9= -1

-1-3= -4

3 0

2 years ago

Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y

ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; $(x^2-4)^2y'' + (x + 2)y' + 7y = 0$

The above equation can be better expressed as:

$y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0$

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

$p(x) = \dfrac{(x+2)}{(x^2-4)^2} \$

$p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \$

$p(x) = \dfrac{1}{(x+2)(x-2)^2}$

Also;

$q(x) = \dfrac{7}{(x^2-4)^2}$

$q(x) = \dfrac{7}{(x+2)^2(x-2)^2}$

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

$\lim \limits_{x \to-2} (x+ 2) p(x) = \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{1}{(x-2)^2}$

$\implies \dfrac{1}{16}$

$\lim \limits_{x \to-2} (x+ 2)^2 q(x) = \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}$

$\implies \lim \limits_{x \to2} \dfrac{7}{(x-2)^2}$

$\implies \dfrac{7}{16}$

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

5 0

2 years ago

A<br> __ +2≤6<br> 5<br><br> Please help

AlladinOne [14]

Answer:

a=3

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers