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andrew11 [14]
4 years ago
9

A researcher was studying how the weights of horseshoe crabs along the East Coast vary between northern and southern habitats. I

n spring 2006, during breeding season, the researcher randomly selected 50 horseshoe crabs in southern habitats. In fall 2006, before the breeding season began, the researcher randomly selected 50 horseshoe crabs from northern habitats. It was found that crabs in southern habitats weighed more, so the researcher claimed that location had an effect on the weight of horseshoe crabs.
The response variable in this experiment is:_______.
A, the different habitat locations.
B. the crabs
C. the season each sample was taken.
D. the weight of the crab
Mathematics
1 answer:
Ronch [10]4 years ago
6 0

Answer:

Option D (the weight of crab) would be the correct choice.

Step-by-step explanation:

  • In mathematics, the sum being analyzed depending on a variety of parameters, which have been calculated as explanatory variables, has become a response variable.
  • It is analogous with the utilization of the definition of variables of the study. A variable with an order to respond is categorized as either a dependent variable.

Some other preferences are not connected with the sustaining. So choice D is the right one.

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In a figure, OB is the radius of a big semicircle and XB is the radius of the small semicircle. Given that OX = 14 cm, Calculate
oee [108]

Answer:

perimeter of the shaded region = 88 +44+28 =160 cm

Step-by-step explanation:

perimeter of shaded region = length AO + arc OB + arc AB

length AO = radius of bigger circle

radius of bigger circle = OX + OB = 2×radius of smaller circle = 2×14 cm = 28 cm

therefore AO = 28 cm

length of arc oB= half of circumference of smaller circle = \pi×14 = 44 cm

length of arc ab = half of circumference of bigger circle  = \pi×28 =\frac{22}{7}×28= 88

therefore perimeter of the shaded region = 88 +44+28 =160 cm

area of the shaded region = half of area of bigger circle - half of area of smaller circle

                                           =\frac{1}{2} \pi 28^{2} -\frac{1}{2} \pi 14^{2}

                                           =\frac{\pi }{2} (28^{2} -14^{2} )

  solving we gen area of shaded region = 924

7 0
3 years ago
Describe the relationship. Check all that apply.
AlekseyPX

Answer:

this is a negative association

Step-by-step explanation:

4 0
3 years ago
Serenity Spa charges $59 for a one hour massage. They charge $0.95 per minute for each additional minute over an hour. If
Yanka [14]

Answer:

D. y = 0.8x + 79

Choices:

A.  

y = 79x + 0.8

B.  

y = -0.8x + 79

C.  

y = 79.8x

D.  

y = 0.8x + 79

5 0
3 years ago
Using the foil method, multiply the terms of the binomials below. Show your work in the blanks provided. Then, add any like term
aalyn [17]

Answer:

5x^4+7x^3-6x^2

Step-by-step explanation:

(x^{2} +2x)(5x^{2} -3x)\\\= 5x^{4}-3x^{3} +10x^{3}  -6x^{2}\\= 5x^{4}+7x^{3} -6x^{2}

7 0
3 years ago
Find the perimeter of pentagon STUVW WITH VERTICES S(0,0) T(3,-2) U(2,-5) V(-2,-5) W(-3,-2)
andrew11 [14]
Use the distance formula.

\sqrt{( x_{2} - x_{1} )^2 + (y_{2} - y_{1})^2}

 
Points S and W.
\sqrt{(3)^2 + (2)^2}

\sqrt{9+4}

\sqrt{13}

~3.6

Points S and T
\sqrt{(3 - 0)^2 + (-2 - 0)^2}

\sqrt{(3)^2 + (-2)^2}

\sqrt{9+4}

\sqrt{13}

~3.6

Points T and U
\sqrt{(3 - 2)^2 + (-2 + 5)^2}

\sqrt{(1)^2 + (3)^2}

\sqrt{1+9}

\sqrt{10}

~3.1

Points U and V
\sqrt{(2+2)^2 + (-5 + 5)^2}

\sqrt{(4)^2 + (0)^2}

\sqrt{16}

~4

Points V and W
\sqrt{(-2+3)^2 + (-5 + 2)^2}

\sqrt{(1)^2 + (-3)^2}

\sqrt{2+9}

\sqrt{11}

~3.3

Add all these together.

3.3 + 3.1 + 4 + 3.1 + 3.6
≈17
4 0
4 years ago
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