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andrew11 [14]
4 years ago
9

A researcher was studying how the weights of horseshoe crabs along the East Coast vary between northern and southern habitats. I

n spring 2006, during breeding season, the researcher randomly selected 50 horseshoe crabs in southern habitats. In fall 2006, before the breeding season began, the researcher randomly selected 50 horseshoe crabs from northern habitats. It was found that crabs in southern habitats weighed more, so the researcher claimed that location had an effect on the weight of horseshoe crabs.
The response variable in this experiment is:_______.
A, the different habitat locations.
B. the crabs
C. the season each sample was taken.
D. the weight of the crab
Mathematics
1 answer:
Ronch [10]4 years ago
6 0

Answer:

Option D (the weight of crab) would be the correct choice.

Step-by-step explanation:

  • In mathematics, the sum being analyzed depending on a variety of parameters, which have been calculated as explanatory variables, has become a response variable.
  • It is analogous with the utilization of the definition of variables of the study. A variable with an order to respond is categorized as either a dependent variable.

Some other preferences are not connected with the sustaining. So choice D is the right one.

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Pls help and show work I will mark brainliest if correct no spam or else I will report
postnew [5]
Which question? 2 or 3.
5 0
3 years ago
A 9.85 m ladder is placed against a wall. The height to the top of the ladder is 5 m more than the distance between the wall and
Dafna1 [17]

Given:

Length of the ladder = 9.85 m

The height to the top of the ladder is 5 m more than the distance between the wall and the foot of the ladder.

To find:

The height to the top and the distance between the wall and the foot of the ladder.​

Solution:

let x be the distance between the wall and the foot of the ladder. Then the height to the top of the ladder is (x+5).

Pythagoras theorem: In a right angle triangle,

Hypotenuse^2=Base^2+Perpendicular^2

In the given situation, hypotenuse is the length of ladder, i.e., 9.85 m. The base is x m and the height is (x+5) m.

Using the Pythagoras theorem, we get

(9.85)^2=x^2+(x+5)^2

97.0225=x^2+x^2+10x+25

0=2x^2+10x+25-97.0225

0=2x^2+10x-72.0225

Here, a=2, b=10,c=-72.0225. Using the quadratic formula, we get

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\dfrac{-10\pm \sqrt{(10)^2-4(2)(-72.0225)}}{2(2)}

x=\dfrac{-10\pm \sqrt{676.18}}{4}

Approximating the value, we get

x=\dfrac{-10\pm 26}{4}

x=\dfrac{-10+26}{4},\dfrac{-10-26}{4}

x=\dfrac{16}{4},\dfrac{-36}{4}

x=4,-9

Distance cannot be negative so x\neq -9.

Now we have x=4

x+5=4+5

x+5=9

Therefore, the base is 4 m and the height is 9 m.

5 0
3 years ago
How to evaluate (9/16)^-2
Sophie [7]
The correct answer is b. When raising a number to a negative power switches the denominator and the numerator.
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3 years ago
If a person rows to his favorite fishing spot 14 miles downstream in the same amount of time that he rows 2 miles upstream and i
Maru [420]

We will use distance formula which states:

d=r \times t

where 'd' is the distance, 'r' is rate or speed and 't' is time taken.

So, t=\frac{d}{r}

Let 'u' be the speed of boat in still water.

A person rows 14 miles downstream to the fishing spot.

So, the speed of boat downstream = (u+6) mph

Time taken by boat to go downstream = \frac{14}{u+6} hr

He rows 2 miles upstream from the fishing spot.

So, the speed of boat upstream = (u-6) mph

Time taken by boat to go upstream = \frac{2}{u-6} hr

Since, The person took same amount of time in going downstream and then going upstream.

So, \frac{14}{u+6}=\frac{2}{u-6}

Cross multiplying, we get

14 (u-6)= 2(u+6)

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Now, Time taken in going downstream = \frac{14}{u+6}

= \frac{14}{8+6}

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So, total time taken to cover 16 miles is 2 hours.

8 0
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How do I factor y^2-2y-24
rusak2 [61]
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6 0
3 years ago
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