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3 years ago

Consider the triangle.

Mathematics

2 answers:

rjkz [21]3 years ago

6 0

Answer:

you haven't asked a question....

butalik [34]3 years ago

3 0

Answer:

BC= $a\sqrt{3}$ ; a=5

BC= $5\sqrt{3}$

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PLS HELP ME!!!! ASAP I WILL MARK BRAINLIEST!!!!!!

julsineya [31]

Answer:

(-3)^3 x^5

Step-by-step explanation:

x*x*x*x*x *(-3)*(-3)*(-3)

There are 5 x terms

x^5

There are 3 (-3) terms

(-3)^3

Multiply theses together

(-3)^3 x^5

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3 years ago

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PLEASE PLEASE TRANSLATING A SENTENCE INTO AN EQUATION

wariber [46]

Answer:

j - 21 = 58

Step-by-step explanation:

happy to help if you have any others i can help you

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2 years ago

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The mechanic does 4 oil changes in 2 hours. How many oil changes can the mechanic do in 8 hours?

netineya [11]

Answer:

16.

Step-by-step explanation:

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2 years ago

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Find the slope of the line shown on the graph to the right

katrin2010 [14]

Answer:

it is 5/5, or if that doesn't work its 1 just in case you need to simplify

Step-by-step explanation:

from the first point, count how many squares go up, the count how many squares to the right, so up 5 over 5

3 0

2 years ago

Jamie is buying 5 concert tickets, and he wants his total cost to be no more than $4 Above or below $80. Which inequality models

kumpel [21]

Answer:

Option C $\left|80-5x\right|\le 4$

Step-by-step explanation:

Let

x ----> the cost of the concert ticket

we know that

The total cost to be no more than $4 Above $80

$5x\leq 80+4$

Solve for x

$x\leq \$16.80$

The total cost to be no more than $4 below $80

$5x\geq 80-4$

Solve for x

$5x\geq 76$

$x\geq \$15.2$

therefore

The inequality that represent this problem is

$\left|5x-80\right|\le 4$

Verify

First solution (positive case)

$+(5x-80)\le 4$

$5x\le 80+4$

Solve for x

$x\leq \$16.80$ ----> is ok

Second solution (negative case)

$-(5x-80)\le 4$

Multiply by -1 both sides

$(5x-80)\ge -4$

$5x\geq 80-4$

Solve for x

$5x\geq 76$

$x\geq \$15.2$ ---> is ok

Remember that

$\left|5x-80\right|\le 4$ is equivalent to $\left|80-5x\right|\le 4$

Because is a absolute value

8 0

3 years ago