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Galina-37 [17]
3 years ago
10

Consider the triangle.

Mathematics
2 answers:
rjkz [21]3 years ago
6 0

Answer:

you haven't asked a question....

butalik [34]3 years ago
3 0

Answer:

BC= a\sqrt{3}; a=5

BC=5\sqrt{3}

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A line crosses the coordinates (-3,5) and (4, -2). What is the slope-
NeTakaya

Answer:

y=-x+8

Step-by-step explanation:

y = mx + b is the basic formula

use the formula y2-y1/x2-x1 to get the slope to get m

-2-5/4-(-3)

-7/7

-1

then use the point slope formula y-y₁=m(x-x₁)

y-5=-1(x-(-3)

y-5=-1x+3

y=-x+8

6 0
2 years ago
Determine an expression that would represent the area of the figure shown.
Alborosie

Answer:

Option A : 15x² + 62x + 63 is the correct answer.

Step-by-step explanation:

Given measurements of the figure are:

5x + 9 and 3x + 7

We have to find the area. We can find the area by multiplying the two expressions.

Area = (5x+9) * (3x+7)

Area = 5x (3x+7) +9(3x+7)

Area = 15x² + 35x + 27x + 63

Area = 15x² + 62x + 63

Hence,

Option A : 15x² + 62x + 63 is the correct answer.

8 0
2 years ago
What is the equation of the line that contains the point (-5, -1) and has a slope of 4? Write in slope-intercept form.
Zarrin [17]

\huge{\boxed{\text{B.}\ y=4x+19}}

Point-slope form is y-y_1=m(x-x_1), where m is the slope and (x_1, y_1) is a point on the line.

Substitute the values. y-(-1)=4(x-(-5))

Simplify the negative subtraction. y+1=4(x+5)

Distribute the 4. y+1=4x+20

Subtract 1 on both sides. \boxed{y=4x+19}

3 0
3 years ago
Read 2 more answers
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Answer:

tanA/2.

Step-by-step explanation:

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* secA = 1/cosA

* cscA = 1/sinA

* cotA = cosA/sinA

1/sinA - cotA

1/sinA - cosA/sinA

1 - cosA / sinA

.... 1 - cosR / sinR = tan(R/2)

1 - cosA / sinA

= tanA/2.

6 0
2 years ago
Simplify<br> PLZ HELP QUICKLY
elena-14-01-66 [18.8K]

Answer:

c

Step-by-step explanation:

3 0
3 years ago
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