W = m g weight of drop
W = q E
m = q E / g = = 3 e E / g
m = 3 * 1.6E-19 * 1.4E4 / 9.8 = 6.96E-16 kg
If the ground is level, then the snowball can never have
any more kinetic energy than it hand when it left your hand.
If more mass sticks to it as it makes its way across the lawn,
then it must slow down, so that its
KE = (1/2) (present mass) (present speed)²
never exceeds the KE you gave it when you tossed it.
And we're not even talking yet about all the energy it loses
by scraping through the snow and mashing down the blades
of grass in its path.
Answer:
λ₂ = 1.8 m
Explanation:
given,
wavelength of the string 1 = 0.90 m
frequency of the string 1 = 600 Hz
wavelength of string 2 = ?
frequency of the string 2 = 300 Hz
we now,

now,


λ₂ = 2 x 0.9
λ₂ = 1.8 m
Hence, the wavelength of the second string is equal to λ₂ = 1.8 m
Answer:
5m/s to the right
Explanation:
Momentum = mass * velocity
Momentum before = momentum after
m₁u₁+m₂u₂ = m₁v₁+m₂v₂
3000*10 + 1000*0 = 3000*v₁ + 1000*15
30000-15000=3000v₁
15000=3000v₁
v₁=5m/s to the right (to the right because answer is positive)
Answer
given,
range of the projectile = 4.3 m
time of flight = T = 0.829 s


v = 5.19 m/s
vertical component of velocity of projectile
v_y = gt'



a) Launch angle


θ = 38°
b) initial speed of projectile


v = 6.59 m/s
c) maximum height reached by the projectile


