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3 years ago

The energies of electrons are said to be quantized. Explain what this means. please explain.

1 answer:

8 0

To move from one energy level to another, an electron must gain or lose just the right amount of energy. Electrons are said to be quantized because they need a quantum of energy to move to a different sublevel. ... When atoms absorb energy, electrons move into higher energy levels.

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Which gas giant has a rotation axis so tilted that the planet rotated like a bowling ball as it orbits the sun?

Anestetic [448]

The answer to your question is OPTION B

3 0

3 years ago

Please Its urgent I need your HELP!!!!!!!!!!!!!!!!!!!!!!!

ozzi

Raising the temperature results in the radiator giving off photons of high-energy ultraviolet light. As heat is added, the radiator emits photons across a wide range of visible-light frequencies

4 0

3 years ago

Write two different unit in which mass is measured.

inessss [21]

Answer:

kilograms and grams

Explanation:

kilograms is the stadard unit for mass according to the SI system.

Grams is another unit for mass.

5 0

2 years ago

Two black holes (the remains of exploded stars), separated by a distance of

jolli1 [7]

The largest mass is 4.7 x 10³⁰ kg and the smallest mass is 5 x 10²⁹ kg.

The given parameters;

distance between the two black holes, r = 10 AU = 1.5 x 10¹² m
gravitational force between the two black holes, F = 6.9 x 10²⁵ N.
combined mass of the two black holes = 5.20 x 10³⁰ kg

The product of the two masses is calculated from Newton's law of universal gravitational as follows;

$F = \frac{Gm_1m_2}{r^2} \\\\m_1m_2 = \frac{Fr^2}{G} \\\\m_1m_2 = \frac{(6.9\times 10^{25}) \times (1.5\times 10^{12})^2}{6.67\times 10^{-11}} \\\\m_1m_2 = 2.328 \times 10^{60} \ kg^2$

The sum of the two masses is given as;

m₁ + m₂ = 5.2 x 10³⁰ kg

m₂ = 5.2 x 10³⁰ kg - m₁

The first mass is calculated as follows;

m₁(5.2 x 10³⁰ - m₁) = 2.328 x 10⁶⁰

5.2 x 10³⁰m₁ - m₁² = 2.328 x 10⁶⁰

m₁² - 5.2 x 10³⁰m₁ + 2.328 x 10⁶⁰ = 0

solve the quadratic equation using formula method;

a = 1, b =- 5.2 x 10³⁰, c = 2.328 x 10⁶⁰

$m_1 = \frac{-b \ \ +/- \ \ \sqrt{b^2 - 4ac} }{2a} \\\\m_1 = \frac{-(-5.2\times 10^{20}) \ \ +/- \ \ \sqrt{(-5.2\times 10^{20})^2 - 4(1\times 2.328\times 10^{60})} }{2(1)} \\\\m_1 = 4.7 \times 10^{30} \ kg \ \ or \ \ 4.9 \times 10^{29} \ kg$

The second mass is calculated as follows;

m₂ = 5.2 x 10³⁰ kg - m₁

m₂ = 5.2 x 10³⁰ kg - 4.7 x 10³⁰ kg

m₂ = 5 x 10²⁹ kg

m₂ = 5.2 x 10³⁰ kg - 4.9 x 10²⁹ kg

m₂ = 4.7 x 10³⁰ kg

Thus, the largest mass is 4.7 x 10³⁰ kg and the smallest mass is 5 x 10²⁹ kg.

Learn more here:brainly.com/question/9373839

3 0

2 years ago

The emissivity of galvanized steel sheet, a common roofing material, is 0.13 at temperatures around 300 K, while its absorptivit

vfiekz [6]

Answer:

Total heat transfer rate is combined convection and radiation transfer rate, multiplied with absorptivity factor. From that equation you can find temperature of the roof using iteration method.

Explanation:

Known:

steel sheet roof emissivity ∈ = 0.13

steel sheet roof absorptivity $\alpha$ _s = 0.65

air temperature T∞ = 16°C ...= 289K

heat transfer rate $G_s$ = 750 W/m2

natural convection h = 7W/m2K

Total heat transfer rate is combined heat transfer rate of convection and radiation, multiplied with absorptivity factor:

$\alpha$ $G_s$ = $q_{conv} +q_{rad} =hA($ T∞- $T_m$ )+∈σA( $T_{surf} -T_{s} )$

$\alpha$ $G_s$ - $h(T_s-$ T∞)-∈σ( $T_{s} -T_{surf} )$ =0

2562-7 $T_s$ -7.371*10^-9=0

Use iteration method to solve for $T_s$

$T_s$ =350.17 K...=77.17°C

In this particular situation, cat would not be comfortable with walking on a roof since its surface temperature is 77.17°C which may even cause burns to its paws.

4 0

3 years ago