All categories

2 years ago

Both acids and bases produce ions when dissolved in water. Propose a way to describe what

Physics

2 answers:

Ber [7]2 years ago

7 0

What he said I just need points and I wanna look hella smart

EleoNora [17]2 years ago

6 0

Answer:

See explanation

Explanation:

Acids and bases contain ions that interact with water. According to the Arrhenius definition, acids are substances that produce hydrogen ion in water while bases are substances that produce hydroxide ion in water.

The pH scale is a graphic description of the hydrogen or hydroxide ion present in a sample. Since pH= -log[H^+], the higher the pH , the lower the hydrogen ion concentration and vice versa.

Similarly, pOH= -log [OH^-] , hence the more the OH^- concentration the lower the pOH.

However pH + pOH =14.

Thus the concentration of hydrogen or hydroxide ions present determines the pH of any solution.

You might be interested in

Bird bones have air pockets in them to reduce their weight—this also gives them an average density significantly less thanthat o

snow_tiger [21]

Answer:

41.4 g

41.4 cm³

1.08695 g/cm³

Explanation:

$\rho$ = Density of water = 1 g/cm³

Mass of water displaced will be the difference of the

$m=45-3.6\\\Rightarrow m=41.4\ g$

Mass of water displaced is 41.4 g

Density is given by

$\rho=\dfrac{m}{v}\\\Rightarrow v=\dfrac{m}{\rho}\\\Rightarrow v=\dfrac{41.4}{1}\\\Rightarrow v=41.4\ cm^3$

So, volume of bone is 41.4 cm³

Average density of the bird is given by

$\rho=\dfrac{45}{41.4}\\\Rightarrow \rho=1.08695\ g/cm^3$

The average density is 1.08695 g/cm³

3 0

2 years ago

A 7.5-cmcm-diameter horizontal pipe gradually narrows to 4.5 cmcm . When water flows through this pipe at a certain rate, the ga

tino4ka555 [31]

Answer

given,

diameter,d₁ = 7.5 cm

d₂ = 4.5 cm

P₁ = 32 kPa

P₂ = 25 kPa

Assuming, we have calculation of flow in the pipe

using continuity equation

A₁ v₁ = A₂ v₂

π r₁² v₁ = π r₂² v₂

$v_1= \dfrac{r_2^2}{r_1^2} v_2$

$v_1= \dfrac{2.25^2}{3.75^2} v_2$

$v_1= 0.36 v_2$

Applying Bernoulli's equation

$\Delta P = \dfrac{1}{2}\rho (v_2^2-v_1^2)$

$P_1-P_2 = \dfrac{1}{2}\rho (v_2^2-(0.36 v_2)^2)$

$32-25 = \dfrac{1}{2}1000\times v_2^2 (1 - 0.1269)$

$v_2=\sqrt{\dfrac{2\times 7\times 10^3}{1000\times (0.8704)}}$

$v_2=\sqrt{16.084}$

v₂ = 4.01 m/s

fluid flow rate

Q = A₂ V₂

Q = π (0.0225)² x 4.01

Q = 6.38 x 10⁻³ m³/s

flow in the pipe is equal to 6.38 x 10⁻³ m³/s

4 0

2 years ago

2.0 mol of monatomic gas A initially has 5000 J of thermal energy. It interacts with 3.0 mol of monatomic gas B, which initially

Naddika [18.5K]

Answer:

E_particle = 1,129 10⁻²⁰ J / particle

T= 817.5 K

Explanation:

Energy is a scalar quantity so it is additive, let's look for the total energy of each gas

Gas a

E_a = 2 5000 = 10000 J

Gas b

E_b = 3 8000 = 24000 J

When the total system energy is mixed it is

E_total = E_a + E_b

E_total = 10000 + 24000 = 34000

The total mass is

M = m_a + m_b

M = 2 +3 = 5

The average energy among the entire mass is

E_averge = E_total / M

E_averago = 34000/5

E_average = 6800 J

One mole of matter has Avogadro's number of atoms 6,022 10²³ particles

Therefore, each particle has an energy of

E_particle = E_averag / 6.022 10²³ = 6800 /6.022 10²³

E_particle = 1,129 10⁻²⁰ J / particle

For find the temperature let's use equation

E = kT

T = E / k

T = 1,129 10⁻²⁰ / 1,381 10⁻²³

T = 8.175 102 K

T= 817.5 K

5 0

2 years ago

A player holds two baseballs a height h above the ground. He throws one ball vertically upward at speed v0 and the other vertica

Degger [83]

Answer:

a) v = √(v₀² + 2g h), b) Δt = 2 v₀ / g

Explanation:

For this exercise we will use the mathematical expressions, where the directional towards at is considered positive.

The velocity of each ball is

ball 1. thrown upwards vo is positive

v² = v₀² - 2 g (y-y₀)

in this case the height y is zero and the height i = h

v = √(v₀² + 2g h)

ball 2 thrown down, in this case vo is negative

v = √(v₀² + 2g h)

The times to get to the ground

ball 1

v = v₀ - g t₁

t₁ = $\frac{v_{o} - v }{ g}$

ball 2

v = -v₀ - g t₂

t₂ = - \frac{v_{o} + v }{ g}

From the previous part, we saw that the speeds of the two balls are the same when reaching the ground, so the time difference is

Δt = t₂ -t₁

Δt = $\frac{1}{g} \ [(v_{o} - v) - ( - v_{o} - v) ]$

Δt = 2 v₀ / g

6 0

2 years ago

A strong man and a weak man are trying to carry a ladder . How should they carry it in such a way that the weak person feels les

dsp73

Answer:

The strong person should carry the ladder at the front end and the weak person should carry it at the back end.

Explanation:

this is because in such a case the strong person has to pull the ladder whereas the weak person at the back end have to push the ladder. In such case it is easier to push because the weak person can use the force of gravity of his own body for pushing the ladde.

However in case of pulling the ladder one has to overcome his own gravity to pull the heavy object

7 0

2 years ago

Read 2 more answers