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stira [4]
2 years ago
10

When the current through a circular loop is 5.7 A, the magnetic field at its center is 3.9 ✕ 10−4 T. What is the radius (in m) o

f the loop?
Physics
1 answer:
borishaifa [10]2 years ago
8 0

Radius of the circular loop is 0.0091m.

<h3>What is magnetic field?</h3>

Magnetic field is the area around a magnet where the magnetism influence is felt .

<h3>What is the magnetic field at the centre of a circular loop?</h3>
  • The formula for magnetic field at the centre of a loop is

B =(μ)I/2r

  • where B= Magnetic field at the centre of a circular loop

μ= Magnetic permeability =4(π)*10^(-7)

I= current flowing through the loop

r= radius of the loop

  • Thus, radius of the loop =(4(π)×10^(-7)×5.7)/(2×3.9×10^(-4))

=0.0091m

Thus, we can conclude that the radius of the loop is 0.0091m .

Learn more about magnetic field here :

brainly.com/question/24761394

#SPJ1

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Answer:

Under the reasonable assumption that the brick has more mass than the feather, the brick experiences a greater force of air friction.

Explanation:

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Under the reasonable assumption that the brick has more mass than the feather, the brick experiences a greater force of air friction.

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Answer:

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Explanation:

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K=\frac{mv^2}{2}

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For our case then we have:

\Delta K = K_f-K_i=\frac{mv_f^2}{2}-\frac{mv_i^2}{2}=\frac{m(v_f^2-v_i^2)}{2}

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\Delta K = \frac{m(v_f^2-v_i^2)}{2} = \frac{(26Kg)((2m/s)^2-(0m/s)^2)}{2} = 52J

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