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AfilCa [17]
4 years ago
12

When transiting a great distance a Navigator prepares a __________ track so the ship can steady courses while driving the shorte

st distance.
Physics
2 answers:
coldgirl [10]4 years ago
7 0

Answer:

composite track

Explanation:

To travel an incredible circular track, the guide must constantly change course because the extraordinary circular track is a turn when plotted on a Mercator map. It is ridiculous to try to navigate an incredible circular route. All things considered, to make the best use of the shorter cruise separation from the extraordinary circular runway, pilots generally divide an incredible hover runway between the underlying position and the target into many much smaller sections ( for trajectory purposes) of approximately one to several days of cruising time (based clearly on the specialty and conditions) and making course changes every day simultaneously, generally in the early afternoon. Absolute separation is thus the set of separations of these fragments determined by the methods of Mercator Sailing. A potential problem with the incredible circular track, however, is the most limited route between two areas, similarly for most tracks closer to the well (or at a higher range) than the two points, starting point or goal. The high areas are often in danger due to the terrible climate and icing. A protected thought of a veteran sailor is to set a range limit for the long voyage plan. This arrangement is called an extraordinary composite circle course arrangement, terminated with way points. This minicomputer soothes the monotonous procedure for deciding these way points for travel.

Yakvenalex [24]4 years ago
6 0

Answer:

The answer is composite track.

Explanation:

For ships to cover the shortest distance between two points on the surface of the earth, navigators base their calculations using great circles. A great circle is circular line drawn on a globe that follows the circumference of the earth ( thereby dividing the globe into equal halves ).  As the ship moves from one point to the other, the navigator adjusts its course because the earth is on a constant rotation. Great circles, because they usually cover distances of about 40,000km are broken down into smaller lines called Rhumb so as to provide a steady course. The one common great circle is the equator and the ship's heading does not change on this line.

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2.
Afina-wow [57]

Answer:

2.76×10⁻¹⁰ C

Explanation:

Applying,

V = W/q................... Equation 1

Where V = Electric Potential, E = Electric potential energy, q = charge.

make q the subject of the equation

q = W/V................ Equation 2

From the question,

Given: W = 4.26×10⁻⁸ J, V = 154.5 V

Substitute these values into equation 2

q = 4.26×10⁻⁸/154.5

q = 2.76×10⁻¹⁰ C

3 0
3 years ago
A block of mass m slides down a frictionless track, then around the inside of a circular loop-the-loop of radius R. From what mi
Oliga [24]

Answer:

H = \frac{5}{2}R

Explanation:

As we know that if the block will complete the circular motion of the path then the speed at the bottom most part of the path must be equal to

v = \sqrt{5Rg}

now we know that

velocity at the bottom of the path is due to conversion of potential energy to kinetic energy

so we can say it is given as

U = KE

mgH = \frac{1}{2}mv^2

now we have

mgH = \frac{1}{2}m(5Rg)

H = \frac{5}{2}R

3 0
3 years ago
Which of the following statements is FALSE about collisions? (Consider Newton's Laws an the Conservation of Momentum.)
pantera1 [17]

<u>The following statements are false about collisions: </u>

  • The velocity change of two respective objects involved in a collision will always be equal.
  • Total momentum is always conserved between any two objects involved in a collision.

Answer: Option B, and D

<u>Explanation: </u>

In any collisions, equal amount of net force will be acted upon the colliding objects due to the third law of Newton, irrespective of the significance difference in mass of the objects. Similarly, they can also have different acceleration values during collision of two objects if the masses are identical.

But the statements regarding the equal change in velocity of two objects respectively involved in collision always is false, as the conservation of momentum is applicable for isolated system only. So it is true for only isolated system and not in all the systems.

The same reason goes for falsifying the fourth statement which states that total momentum is always conserved between two objects involved in a collision as this statement is only true for isolated system where the conservation of momentum can be applied. Thus the second and fourth statement is false regarding collision.

8 0
3 years ago
When the same force id applied to a smaller area, the pressure is A. Lower B.greater C. Reduced D. The same
irakobra [83]
I believe the correct answer is "B. Greater".
7 0
4 years ago
When a space shuttle was launched, the astronauts onboard
kicyunya [14]

Answer:

wow that was so dangerous

3 0
3 years ago
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