Ask question

Ask question

All categories

3 years ago

10

If the magnitude of the resultant force is to be 500n, directed along the positive y axis, determine the magnitude of force f an

d its direction

1 answer:

scoundrel [369]3 years ago

5 0

The answer is 0=45.2 degrees

You might be interested in

Ivan walks 10 meters west to the water fountain, then runs 2 meters east to his class to avoid a lockout. His displacement would

otez555 [7]

Answer:

<u>-8</u>

Explanation:

if he starts at ten and takes 10 steps left he'll be at -10... then if he takes 2 steps to the right , he's at -8 on the number-line

7 0

3 years ago

Read 2 more answers

Two technicians are discussing service information. Technician A says that online service information is only available from the

Westkost [7]

The correct one is A. Technician Only.
The distribution of service information is regulated by <span>United States Environmental Protection Agency.
According to the rules, all vehicle manufacturers are required to make their service information available for everyone online for 'reasonable prices'.
Because of this, vehicle manufacturers started discontinuing the paper format.</span>

4 0

3 years ago

Of the three sciences, physics, chemistry, and biology, the most complex is

Agata [3.3K]

Answer:

I would probably say C to be completely honest

Explanation:

If you agree make sure to give me a like

6 0

2 years ago

Find deacceleration An engineer in a locomotive sees a car stuck on the track at a railroad crossing in front of the train. When

earnstyle [38]

Answer:

The deceleration is $a = -0.7273 \ m/s^2$

Explanation:

From the question we are told that

The distance of the car from the crossing is $d = 360 \ m$

The speed is $u = 16 \ m/s$

The reaction time of the engineer is $t = 0.53 \ s$

Generally the distance covered during the reaction time is

$d_r = u * t$

=> $d_r = 16 * 0.53$

=> $d_r = 8.48 \ m$

Generally distance of the car from the crossing after the engineer reacts is

$D = d- d_r$

=> $D = 360 - 8.48$

=> $D = 352 \ m$

Generally from kinematic equation

$v^2 = u^2 + 2as$

Here v is the final velocity of the car which is 0 m/s

So

$0^2 = 16^2 + 2 * a * 352$

=> $a = -0.7273 \ m/s^2$

3 0

2 years ago

A child is riding a merry-go-round that has an instantaneous angular speed of 12 rpm. If a constant friction torque of 12.5 Nm i

sammy [17]

Answer:

$-0.25 rad/s^2$

Explanation:

The equivalent of Newton's second law for rotational motions is:

$\tau = I \alpha$

where

$\tau$ is the net torque applied to the object

I is the moment of inertia

$\alpha$ is the angular acceleration

In this problem we have:

$\tau = -12.5 Nm$ (net torque, with a negative sign since it is a friction torque, so it acts in the opposite direction as the motion)

$I=50.0 kg m^2$ is the moment of inertia

Solving for $\alpha$ , we find the angular acceleration:

$\alpha = \frac{\tau}{I}=\frac{-12.5 Nm}{50.0 kg m^2}=-0.25 rad/s^2$

3 0

3 years ago