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mote1985 [20]
3 years ago
5

Is peridotite a mineral,a rock,or neither

Chemistry
2 answers:
PolarNik [594]3 years ago
8 0

Answer: A rock

Explanation: Peridotite is a dense, coarse-grained igneous rock consisting mostly of the minerals olivine and pyroxene.

mamaluj [8]3 years ago
4 0

Answer: a rock

Explanation:

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PLS HELP ASAP I WILL GOVE BRAINLYEST
Radda [10]

Answer:

4 genetically different daughter cells

Explanation:

in image

5 0
3 years ago
1 point
Bumek [7]

Answer:

1 mole of C2H6.

Explanation:

The balanced equation for the reaction is given below:

2C2H6 + 7O2 —> 4CO2 + 6H2O

We can determine the number of mole of C2H6 that reacted to produce 2 moles of CO2 as follow:

From the balanced equation above,

2 moles of C2H6 reacted to produce 4 moles of CO2.

Therefore, Xmol of C2H6 will react to produce 2 moles of CO2 i.e

Xmol of CO2 = (2 x 2)/4

Xmol of CO2 = 1 mole.

Therefore, 1 mole of C2H6 is required to produce 2 moles of CO2.

6 0
3 years ago
Question
madam [21]

Answer:

The specific heat of the metal is 2.09899 J/g℃.

Explanation:

Given,

For Metal sample,

mass = 13 grams

T = 73°C

For Water sample,

mass = 60 grams

T = 22°C.

When the metal sample and water sample are mixed,

The addition of metal increases the temperature of the water, as the metal is at higher temperature, and the  addition of water decreases the temperature of metal. Therefore, heat lost by metal is equal to the heat gained by water.

Since, heat lost by metal is equal to the heat gained by water,

Qlost = Qgain

However,

Q = (mass) (ΔT) (Cp)

(mass) (ΔT) (Cp) = (mass) (ΔT) (Cp)

After mixing both samples, their temperature changes to 27°C.

It implies that , water sample temperature changed from  22°C to 27°C and metal sample temperature changed from 73°C to 27°C.

Since, Specific heat of water = 4.184 J/g°C

Let Cp be the specific heat of the metal.

Substituting values,

(13)(73°C - 27°C)(Cp) = (60)(27°C - 22℃)(4.184)

By solving, we get Cp =

Therefore, specific heat of the metal sample is 2.09899 J/g℃.

5 0
3 years ago
Density is ___ to pressure
Ann [662]
Proportional to pressure
5 0
3 years ago
What is the pH of a solution of 0.800 M KH2PO4, potassium dihydrogen phosphate?
Nookie1986 [14]
KH₂PO₄ hydrolyzes as;
H₂PO₄⁻ + H₂O ↔ H₃PO₄ + OH⁻
Let x amount of H₂PO₄⁻ has reacted with water then,
Kb₁ = [H₃PO₄][OH⁻] / [H₂PO₄⁻]
[H₂PO₄⁻] = 0.8-x M
Kb₁ = x² / (0.8 - x)
Given Ka₁ = 7.5 x 10⁻³
so Kb₁ = 1 x 10⁻¹⁴ / (7.5 x 10⁻³) = 1.33 x 10⁻¹²
From this information:
1.33 x 10⁻¹² = x² / 0.8
x = [OH⁻] = 1.03 x 10⁻⁶ M
pOH = - log (1.03 x 10⁻⁶) = 5.99
pH = 14 - pOH = 14 - 5.99 = 8.01 



3 0
3 years ago
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