Which quantity is a vector quantity?

The new memory-driven computer being developed by NASA and Hewlett Packard Enterprises is lightweight, hundreds of times faster

sladkih [1.3K]

It is true because the new memory driven developed by NASA

7 0

3 years ago

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A photon detector captures a photon with an energy of 4.29 ✕ 10−19 J. What is the wavelength, in nanometers, of the photon?

serious [3.7K]

Answer : The wavelength of photon is, $4.63\times 10^{2}nm$

Explanation : Given,

Energy of photon = $4.29\times 10^{-19}J$

Formula used :

$E=h\times \nu$

As, $\nu=\frac{c}{\lambda}$

So, $E=h\times \frac{c}{\lambda}$

where,

$\nu$ = frequency of photon

h = Planck's constant = $6.626\times 10^{-34}Js$

$\lambda$ = wavelength of photon = ?

c = speed of light = $3\times 10^8m/s$

Now put all the given values in the above formula, we get:

$4.29\times 10^{-19}J=(6.626\times 10^{-34}Js)\times \frac{(3\times 10^{8}m/s)}{\lambda}$

$\lambda=4.63\times 10^{-7}m=4.63\times 10^{-7}\times 10^9nm=4.63\times 10^{2}nm$

Conversion used : $1nm=10^{-9}m$

Therefore, the wavelength of photon is, $4.63\times 10^{2}nm$

6 0

3 years ago

Can we call centre of gravity centre of weight?

algol [13]

Answer:

Centre of gravity is a theoretical point in the body where the total weight of the body is thought to be concentrated. In a uniform gravitational field, the centre of gravity is identical to the centre of mass. Yet, the two points do not always coincide.

3 0

3 years ago

Large electric fields in cell membranes cause ions to move through the cell wall. The field strength in a typical membrane is 1.

serg [7]

Explanation:

The given data is as follows.

Electric field (E) = $1 \times 10^{7} N/C$

Charge (e) = $1.6 \times 10^{-19}$ C

Formula to calculate the magnitude of force is as follows.

F = qE

= $1.6 \times 10^{-19} \times 1 \times 10^{7} N/C$

= $1.6 \times 10^{-12} N$

Therefore, we can conclude that magnitude of the force on a calcium ion with charge +e is $1.6 \times 10^{-12} N$ .

6 0

3 years ago

An object is placed 96.5 cm from a glass lens (n = 1.51) with one concave surface of radius 24 cm and one convex surface of radi

poizon [28]

Answer:

image is vertical at distance -203.62 cm

magnification is 2.110

Explanation:

given data

n = 1.51

distance u = 96.5 cm

concave radius r1 = 24 cm

convex radius r2 = 19.1 cm

to find out

final image distance and magnification

solution

we will apply here lens formula to find focal length f

1/f = n-1 ( 1/r1 - 1/r2) .......................1

put here all value

1/f = 1.51 -1 ( -1/24 + 1/19.1)

f = 183.43

so from lens formula

1/f = 1/v + 1/u .............................2

put here all value and find v

1/183.43 = 1/v + 1/96.5

so

v = −203.62 cm

so here image is vertical at distance -203.62 cm

and

magnification are = -v /u

magnification = 203.62 / 96.5

magnification is 2.110

3 0

4 years ago