Do heavier bowling balls go faster than lighter ones?

Physics

2 answers:

cricket20 [7]2 years ago

8 0

Answer:

lighter ones will go faster

Explanation:

assuming you throw both bolwing ball with 10N of force. one is 3kg and the other is 5kg.

by using the equation: F = ma

a = F/m

a = 10/5 = 2m/s^2

a = 10/3 = 3.33333 m/s^2

Effectus [21]2 years ago

7 0

Piper rockelle and I just got off the phone number

You might be interested in

Which of the following properties of water help to explain why icebergs float in the ocean?

crimeas [40]

The reason why icebergs float in the ocean has to do with temperature. Icebergs are colder than the ocean water and therefore the cold water is less dense than the warm water and this causes the Iceberg to float.

7 0

2 years ago

What is voltage?

Andrews [41]

<span>C. It is the difference in electrical potential energy between two places in an electric field.</span>

5 0

3 years ago

Read 2 more answers

Which of the following lists are all renewable resources?

earnstyle [38]

The answer is A.

Hydroelectric, which is usually generating electricity through use of a dam.

Solar, energy from the Sun.

Biomass, organic material formed from plant matter.

3 0

3 years ago

in a solar system far, far away the sun's intensity is 200 w/m2 for an inner planet located a distance r away. what is the sun's

GarryVolchara [31]

The sun's intensity for an outer planet located at a distance 6r from the sun is 5.55 W/m². The result is obtained by using the inverse square law formula.

<h3>What is the Inverse Square Law formula?</h3>

The Inverse Square Law formula describes the intensity of light is inversely proportional to the square of the distance. It can be expressed as

$\frac{I_{1} }{I_{2} } = \frac{d_{2}^{2} }{d_{1}^{2}}$

Where

I₁ = Intensity at distance 1 (W/m²)
I₂ = Intensity at distance 2 (W/m²)
d₁ = distance 1 from a light source (m)
d₂ = distance 2 from a light source (m)

Given the case the sun's intensity is 200 W/m² for an inner planet at the distance r. If an outer planet is at a distance 6r, what is the sun's intensity?

By using the inverse square law formula, the sun's intensity for an outer planet is

$\frac{I_{1} }{I_{2} } = \frac{d_{2}^{2} }{d_{1}^{2}}$

$\frac{200 }{I_{2} } = \frac{(6r)^{2} }{r^{2}}$