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Andreyy89
3 years ago
8

When a user utilizes another computer to communicate with a third party, with the result that the third party cannot recognize t

he IP address of the originating communication is called____________.
Computers and Technology
1 answer:
avanturin [10]3 years ago
4 0

Answer:

Online or Web Proxy

Explanation:

Web or online proxy allows you to hide your Internet Protocol (IP) address from the website you are trying to visit or access. It is like a shield between the website you are accessing and you. They can be seen as a middleman between you and the site you are visiting and as such, the site sees that a specific IP address is accessing its server but the address is not yours as all requests between your computer and the web server are first passed through the proxy server.

<em>Hope this helps!</em>

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What does the label display when the user clicks the button? void btnSubmit_Click(object sender, EventArgs e) { int num1 = 3; in
erma4kov [3.2K]

Answer:

10

Explanation:

num1=3 and num2=2

num3=myproc(num1)+myproc(num2)

myproc(num1) results 6

myproc(num2) results 4

when we add both e get 10

6 0
2 years ago
Programming in https<br>​
kakasveta [241]
What?? explain your question
3 0
2 years ago
Consider the following high-level recursive procedure: long long int flong long int n, long long int k long long int b b k+2; if
Stolb23 [73]

Answer:

f(long long, long long):

push rbp

mov rbp, rsp

push rbx

sub rsp, 40

mov QWORD PTR [rbp-40], rdi

mov QWORD PTR [rbp-48], rsi

mov rax, QWORD PTR [rbp-48]

add rax, 2

mov QWORD PTR [rbp-24], rax

cmp QWORD PTR [rbp-40], 0

jne .L2

mov QWORD PTR [rbp-24], 8

jmp .L3

.L2:

mov rax, QWORD PTR [rbp-40]

lea rdx, [0+rax*4]

mov rax, QWORD PTR [rbp-24]

lea rbx, [rdx+rax]

mov rax, QWORD PTR [rbp-48]

lea rdx, [rax+1]

mov rax, QWORD PTR [rbp-40]

sub rax, 1

mov rsi, rdx

mov rdi, rax

call f(long long, long long)

add rax, rbx

mov QWORD PTR [rbp-24], rax

.L3:

mov rdx, QWORD PTR [rbp-24]

mov rax, QWORD PTR [rbp-48]

add rax, rdx

add rsp, 40

pop rbx

pop rbp

ret

Explanation:

8 0
2 years ago
Different network scenarios require the
Vladimir [108]

Answer:

a) Viruses

Explanation:

Vulnerability assessment is performed by variety of tools and these can be protocol analyzer, vulnerability scanner, Honeypots, port scanners, honey nets and banner grabbing tools.

Port scanners : they are used to scan the ports which can be exploited by attackers. Most of TCP/IP applications communicate using different ports and attackers can exploit these ports if they are found vulnerable. for example : ports like 80 and 443 are commonly used for HTTP and SSL communication. 22 is used for SSH and if they are open to world then it will allow attackers to use those to get the entry into the system.

Protocol Analyzers : They are used to analyze the packet captures. tools like wireshark, tshark, these tools will help user to decode HTTP/SSL/HTTPS/FTP/RSTP or any application protocols communication. this will help user to understand any unwanted or non-anticipated traffic.

Vulnerability Scanners : They are used to detect the vulnerabilities in the network or systems. these will help administrators to get the alerts whenever there are unanticipated activity. It will have two types of scanners one is active scanner and other is passive scanner. Active scanners will keep on sending probes at the fixed time slots and passibe scanners will be in listening mode all the time. These scanners will alert when a new nodes comes up or goes down or if any system gets compromised.

Honeypots and Honey nets : They are devices or softwares which are having limited security. These devices are made vulnerable purposefully so that attackers can try and attack.  This will help softwares to detect the attackers when they try to exploit these open vulnerabilities. They are deceptions created with purpose.

Banner grabbing Tools : These are tools which will capture the banner information like HTTP protocol version, underlying operating system, open ssl versions being used, server software and similar information. these are important as it will open up potential vulnerabilities in the underlying software. for ex : SSLv3 has a vulnerability known to world and can be exploited by anyone.

4 0
2 years ago
a 0.600 kg dynamics trolley has 1.5 kg load added. It is launched with a force of 10.n what is the acceleration
Anastaziya [24]

Answer:

acceleration = 4.76 m/s²

Explanation:

Given that"

the mass of the dynamic trolley = 0.6 kg

the mass of the load  = 1.5 kg

total mass = (0.6 + 1.5) kg = 2.1 kg

the force = 10 N

Thus;

using the formula of force which is;

Force = mass × acceleration

10 = 2.1  × acceleration

acceleration = 10/2.1

acceleration = 4.76 m/s²

7 0
2 years ago
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