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VLD [36.1K]
3 years ago
10

Explain how multiplying with 6 is like mutiplying with 3

Mathematics
2 answers:
yulyashka [42]3 years ago
5 0
6 and 3 can give you the same answer
kvv77 [185]3 years ago
3 0

Answer:

Step-by-step explanation:

6 is simply 3 doubled, any multiple of 6 will be the relative multiplation for 3 doubled.

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Given the parent function f(x) = 2^x, which graph shows f(x) + 1?
mixer [17]

Answer: First Option

a) exponential function going through point (0, 2) and ending up on the right

Step-by-step explanation:

Look at the attached image, the red line represents a function of the form:

f(x) = 2^x

Note that this function cuts to the axis and at the point (0, 1)

Also when x tends to ∞ f(x) tends to ∞ and when f(x) tends to -∞ then f(x) tends to zero.

If we perform the transformation y = f(x) +1 then the graph of y is equal to the graph of f(x) displaced 1 unit up. Then the new cutting point with the axis y will be: (0, 2) as shown in the attached image (blue line)

The transform function is y =2^x +1

Finally the answer is the first option

4 0
3 years ago
Derive this with respect to x<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B%281%20%2B%20%20secx%29%20%7D%20" id="Tex
Elenna [48]

~~~~\dfrac{d}{dx} \left(\dfrac{3}{1 + \sec x} \right)\\\\\\=3 \dfrac{d}{dx} \left( \dfrac 1{ 1+ \sec x} \right)\\\\\\=3 \dfrac{d}{dx} (1+ \sec x)^{-1}\\\\\\=3 (-1) (1 + \sec x )^{-1 -1} \dfrac{d}{dx}( 1 + \sec x)\\\\\\=-3(1 + \sec x)^{-2}  ( 0 + \sec x  \tan x)\\\\\\=-\dfrac{3\sec x \tan x}{(1 + \sec x)^2}

8 0
2 years ago
Can you add a whole number to a number with a variable
jeyben [28]
No, u cant. Because they are not like terms

Examples :
1 + 2v....cannot add or subtract because they are not like terms
2v + 4v = 6v...u can if they have exactly the same variable
3x^2 + 2x...cant
x^2 + 4x^2...can...= 5x^2
3 + 3 ....can
2 + 5x...cant

now u can multiply and divide one...u just cant add or subtract them
7 0
3 years ago
What is the value of a+ by when a= 7, b= and c= 1/2 ?
Marat540 [252]

Answer:

a = 7

b =?

c = 1/2

a + by = 0

7 + b × 1/2 = 0

7 + 1/2 b = 0

1/2 b = - 7

b = -7 × 2

b = - 14

a + by

= 7 + - 14 × 1/2

= 7 -14/2

= 7 - 7

= <u>0</u>

Step-by-step explanation:

Id.k if you forgot to write the value of b or not, since the value of b is not given, this will be ur answer.

3 0
3 years ago
A figure has been dilated from the origin by a scale factor of
Darya [45]

Answer:

See Explanation

Step-by-step explanation:

The question has missing details. So, I'll solve using a general assumption.

Let one of the coordinates of the figure be

A = (x,y)

Let the scale factor be n

When dilated, the new figure is:

A' = n * A

A' = n * (x,y)

To return the image back to the original figure, the new scale factor mus be a reciprocal of the previous scale factor i.e. \frac{1}{n}

So:

A = A' * \frac{1}{n}

Substitute n(x,y) for A';

A = n(x,y) * \frac{1}{n}

A = \frac{n(x,y)}{n}

A = (x,y)

Take for instance:

A = (2,3)

n = 2 -- scale factor

A' = n * A

A' = 2 * (2,3)

A' = (4,6)

To get A from A', using the analysis above

A = \frac{1}{2} * (4,6)

A = (2,3)

6 0
3 years ago
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