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almond37 [142]
3 years ago
13

Which energy transition may take place in the atom if its electron has absorbed a photon?

Chemistry
1 answer:
Nitella [24]3 years ago
6 0
When an electron absorbs a photon, a "quantum leap" of its energy transition takes place.
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Draw a physical model that shows the reaction of zinc metal and hydrochloric acid (hydrogen chloride).
Brilliant_brown [7]

Answer:

Zinc + Hydrochloric Acid Zinc Chloride and Hydrogen Gas

Zn + 2HCI - ZnCl2 + H2

Explanation:

Be sure to label your model to clearly show how you are representing the atoms

3 0
3 years ago
Balance the following chemical equation.<br><br> CCl4 -&gt; ___ C+ ___ Cl2
Bingel [31]

Answer:

Explanation:

CCl4 => C + 2Cl2

6 0
3 years ago
Consider 100.0 g samples of two different compounds consisting only of carbon and oxygen. One compound contains 27.2 g of carbon
Pani-rosa [81]

<u>Answer:</u> The ratio of carbon in both the compounds is 1 : 2

<u>Explanation:</u>

Law of multiple proportions states that when two elements combine to form two or more compounds in more than one proportion. The mass of one element that combine with a given mass of the other element are present in the ratios of small whole number. For Example: Cu_2O\text{ and }CuO

  • <u>For Sample 1:</u>

Total mass of sample = 100 g

Mass of carbon = 27.2 g

Mass of oxygen = (100 - 27.7) = 72.8 g

To formulate the formula of the compound, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{27.2g}{12g/mole}=2.26moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{72.8g}{16g/mole}=4.55moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 2.26 moles.

For Carbon = \frac{2.26}{2.26}=1

For Oxygen  = \frac{4.55}{2.26}=2.01\approx 2

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : O = 1 : 2

Hence, the formula for sample 1 is CO_2

  • <u>For Sample 2:</u>

Total mass of sample = 100 g

Mass of carbon = 42.9 g

Mass of oxygen = (100 - 42.9) = 57.1 g

To formulate the formula of the compound, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{42.9g}{12g/mole}=3.57moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{57.1g}{16g/mole}=3.57moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 3.57 moles.

For Carbon = \frac{3.57}{3.57}=1

For Oxygen  = \frac{3.57}{3.57}=1

<u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : O = 1 : 1

Hence, the formula for sample 1 is CO

In the given samples, we need to fix the ratio of oxygen atoms.

So, in sample one, the atom ratio of oxygen and carbon is 2 : 1.

Thus, for 1 atom of oxygen, the atoms of carbon required will be = \frac{1}{2}\times 1=\frac{1}{2}

Now, taking the ratio of carbon atoms in both the samples, we get:

C_1:C_2=\frac{1}{2}:1=1:2

Hence, the ratio of carbon in both the compounds is 1 : 2

8 0
3 years ago
How did the work of louis pasteur help modern day medicine?
drek231 [11]
Pasteur showed that airborne microbes were the cause of disease. Pasteur built on the work of Edward Jenner and helped to develop more vaccines Pasteur’s career showed how conservative the medical establishment was at the time.

6 0
4 years ago
The combustion of how many moles of ethane (C2H6) would be required to heat 851 g of water from 25.0°C to 98.0°C? (Assume liquid
Debora [2.8K]

Answer : The number of moles of ethane required will be 0.166 mole.

Explanation :

First we have to calculate the heat absorbed by water.

q=m\times c\times (T_{final}-T_{initial})

where,

q = heat absorbed = ?

m = mass of water = 851 g

c = specific heat of water = 4.18J/g^oC

T_{final} = final temperature = 98.0^oC

T_{initial} = initial temperature = 25.0^oC

Now put all the given values in the above formula, we get:

q=851g\times 4.18J/g^oC\times (98.0-25.0)^oC

q=259674.14J=259.67kJ         (1 kJ = 1000 J)

Now we have to calculate the moles of ethane required.

\Delta H=\frac{q}{n}

where,

\Delta H = enthalpy of combustion of ethane = 1560.7 kJ/mol (standard value)

q = heat absorbed = 259.67 kJ

n = number of moles of ethane = ?

1560.7kJ/mol=\frac{259.67kJ}{n}

n=\frac{259.67kJ}{1560.7kJ/mol}

n=0.166mole

Therefore, the number of moles of ethane required will be 0.166 mole.

8 0
3 years ago
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