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Nuetrik [128]
3 years ago
13

What is a significant advantage to the cell in having pyruvate dehydrogenase consist of a large

Chemistry
2 answers:
Ierofanga [76]3 years ago
4 0
Glycolysis or glycolysis (from glycos, sugar, lysis, breakdown) is the metabolic pathway responsible for oxidizing glucose to obtain energy for the cell. It consists of 10 consecutive enzymatic reactions that convert glucose into two molecules of pyruvate, which is able to follow other metabolic pathways and thus continue to deliver energy to the body
Stolb23 [73]3 years ago
3 0
<h3>Answer:  <em> Pyruvate dehydrogenase consists of three enzymes: -Pyruvate dehydrogenase, Dihydrolipoyl transacetylase, and Dihydrolipoyl dehydrogenase. The short distance between these enzymes allows channeling of substrates which minimizes the side reactions.</em></h3><h3><em></em></h3>

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Jarvis checked his odometer reading when filling his tank, and then checked it several days later when he filled his tank again.
8_murik_8 [283]

Answer: 26.25 miles per gallon

Explanation: first odometer reading = 65290

Second odometer reading = 65500

Difference in odometer reading = second reading - first reading

= 65500 - 65290 = 210 miles.

If it took 8 gallons to fill his tank, it means

8 gallons will get him 210 miles, therefore 1 gallon will get 210 miles/8gallons = 26.25miles/gallon. Hence he is getting 26.25miles/gallon.

4 0
3 years ago
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Is it possible for the overall charge of an ionic compound to be -1.<br> true<br> false
AnnZ [28]

Answer:

The correct answer is False

8 0
3 years ago
Look at the diagram below.
damaskus [11]

Answer:

it will gain electrons to fill its outer shell

Explanation:

This element is boron which has 5 electrons.

6 0
3 years ago
Express the van der Waals equation of state as a virial expansion in powers of 1/Vm and obtain expressions for B and C in terms
nirvana33 [79]

Answer:

PV_{m} = RT[1 + (b-\frac{a}{RT})\frac{1}{V_{m} } + \frac{b^{2} }{V^{2} _{m} } + ...]

B = b -a/RT

C = b^2

a = 1.263 atm*L^2/mol^2

b = 0.03464 L/mol

Explanation:

In the given question, we need to express the van der Waals equation of state as a virial expansion in powers of 1/Vm and obtain expressions for B and C in terms of the parameters a and b. Therefore:

Using the van deer Waals equation of state:

P = \frac{RT}{V_{m}-b } - \frac{a}{V_{m} ^{2} }

With further simplification, we have:

P = RT[\frac{1}{V_{m}-b } - \frac{a}{RTV_{m} ^{2} }]

Then, we have:

P = \frac{RT}{V_{m} } [\frac{1}{1-\frac{b}{V_{m} } } - \frac{a}{RTV_{m} }]

Therefore,

PV_{m} = RT[(1-\frac{b}{V_{m} }) ^{-1} - \frac{a}{RTV_{m} }]

Using the expansion:

(1-x)^{-1} = 1 + x + x^{2} + ....

Therefore,

PV_{m} = RT[1+\frac{b}{V_{m} }+\frac{b^{2} }{V_{m} ^{2} } + ... -\frac{a}{RTV_{m} }]

Thus:

PV_{m} = RT[1 + (b-\frac{a}{RT})\frac{1}{V_{m} } + \frac{b^{2} }{V^{2} _{m} } + ...]           equation (1)

Using the virial equation of state:

P = RT[\frac{1}{V_{m} }+ \frac{B}{V_{m} ^{2}}+\frac{C}{V_{m} ^{3} }+ ...]

Thus:

PV_{m} = RT[1+ \frac{B}{V_{m} }+ \frac{C}{V_{m} ^{2} } + ...]     equation (2)

Comparing equations (1) and (2), we have:

B = b -a/RT

C = b^2

Using the measurements on argon gave B = −21.7 cm3 mol−1 and C = 1200 cm6 mol−2 for the virial coefficients at 273 K.

b = \sqrt{C} = \sqrt{1200} = 34.64[tex]cm^{3}/mol[/tex] = 0.03464 L/mol

a = (b-B)*RT = (34.64+21.7)*(1L/1000cm^3)*(0.0821)*(273) = 1.263 atm*L^2/mol^2

3 0
3 years ago
Ways to help our environment- please make it specific and explaining what to do and how to do it
Genrish500 [490]
You can pick up any garbage that you see. Talk to people and hear what their ideas are for helping the environmental.
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