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Answer:</h3>
The total concentration of ions in a 0.75 M solution of HCl is 1.5 M
That is; 0.75 M H⁺ and 0.75 M Cl⁻
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Explanation:</h3>
- Concentration or molarity is the number of moles of a compound or an ion contained in one liter of solution. It is measured in moles per liter (M).
- The concentration of ions making a compound is determined by the ratio of moles of the compound and the constituents ions.
- For instance, HCl dissociates to give H⁺ and Cl⁻
HCl(aq) → H⁺(aq) + Cl⁻(aq)
- Therefore, since the mole ratio between HCl and the constituent ions H⁺ and Cl⁻ is 1:1, then 0.75 M of HCl dissociates to give 0.75 M H⁺ and 0.75 m Cl⁻
- Hence the total concentration of ions in a 0.75 M solution of HCl is 1.5 M (0.75 M H⁺ and 0.75 M Cl⁻)
Greenhouse gases act to <u>increase</u> temperatures by <u>absorbing</u> thermal infrared radiation.
We have already learned that Earth's atmosphere is composed often of nitrogen and oxygen. Those gases are transparent to incoming solar radiation. they may be also transparent to outgoing infrared radiation, which means that they do not take in or emit sun or infrared radiation.
The multiplied quantities of greenhouse gases human sports are adding to the environment have dissatisfied the balance that has been in location for the reason that ceases of the closing ice age, including greater greenhouse gases decreases the amount of infrared radiation energy leaving the atmosphere.
Greenhouse gases inside the ecosystem time and again absorb and re-radiate infrared radiation (warmth). strength radiated from Earth's surface as warmth, or infrared radiation is absorbed and re-radiated by using greenhouse gases, impeding the loss of warmth from our surroundings to area.
Learn more about radiations here brainly.com/question/24469662
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Answer:
C. the relative number of atoms of each element, using the lowest whole ratio.
Explanation:
The empirical formula is how we simplify the whole formula to simplify it to its smallest indivisible parts.
It is definitely not the actual number of atoms. If you see an empirical formula, don't think that it's the full thing.
It is also not a representation of a compound to show its atoms' arrangement: this would be a Lewis dot structure, or a ball and stick model, or something similar. We don't use the empirical formula for this purpose.
Answer:
357 g of the transition metal are present in 630 grams of the compound of the transition metal and iodine
Explanation:
In any sample of the compound, the percentage by mass of the transition metal is 56.7%. This means that for a 100 g sample of the compound, 56.7 g is the metal while the remaining mass, 43.3 g is iodine.
Given mass of sample compound = 630 g
Calculating the mass of iodine present involves multiplying the percentage by mass composition of the metal by the mass of the given sample;
56.7 % = 56.7/100 = 0.567
Mass of transition metal = 0.567 * 630 = 357.21 g
Therefore, the mass of the transition metal present in 630 g of the compound is approximately 357 g
