1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sonbull [250]
3 years ago
11

I keep getting them wrong can someone help me pls

Chemistry
1 answer:
Tanya [424]3 years ago
5 0
4. venus fish si du tas fri is di if
You might be interested in
How is it possible for someone to put an ear to a wall and hear someone in the next room?
kvasek [131]
A spund waves can travel through ALMOST everything.
4 0
2 years ago
The addition of 0.275 L of 1.62 M KCl to a solution containing Ag+ and Pb2+ ions is just enough to precipitate all of the ions
musickatia [10]

Answer:

The mass of PbCl₂ is 45.88 grams and the mass of AgCl is 16.48 grams.

Explanation:

As mentioned in the given question, the addition of 0.275 L of 1.62 M KCl is done in a solution that comprise Ag⁺ and Pb²⁺ ions so that all the ions get precipitated. Therefore, the moles of KCl present is,  

Moles of KCl = 0.275 L × 1.62 M = 0.445 moles

Now the reaction will be,  

Ag⁺ + Pb²⁺ + KCl ⇒ AgCl + PbCl₂ + 3K⁺

Now let us assume that the formation of x moles of AgCl and y moles of PbCl₂ is taking place.  

Therefore, mass of AgCl will be x × molecular mass, which will be equal to x × 143.32 grams = 143.32 x grams

Now the mass of PbCl2 formed will be,  

y × molecular mass = y × 278.1 grams = 278.1 y grams

Now the total precipitate will be,  

62.37 grams = 143.32 x + 278.1 y -----------(i)

Now as AgCl and PbCl₂ requires 1:2 ratio of KCl, this shows that x moles of AgCl will require x moles of KCl and y mol of PbCl₂ will require 2*y moles of PbCl₂. Therefore,  

x + 2y = total mass of KCl

x + 2y = 0.445 moles ------ (ii)

On solving equation (i) and (ii) we get,  

x as 0.115 and y as 0.165

Now the mass of AgCl will be,  

143.32 × 0.115 = 16.48 grams

The mass of PbCl₂ will be,  

278.1 × 0.165 = 45.88 grams.  

3 0
3 years ago
Write the net chemical equation for the production of nitric acid from nitrogen, hydrogen and oxygen. be sure your equation is b
Natalija [7]
<span>Nitric acid is often manufactured from the atmospheric gases nitrogen and oxygen, plus hydrogen prepared by reforming of natural gas, in a two-step process. In the first step, nitrogen and hydrogen react to form ammonia: In the second step, ammonia and oxygen react to form nitric acid and water:</span>
5 0
3 years ago
How many kilojoules are required to melt 15g of ice at 0c and raise the temperature of the liquid that forms to 85c?
timofeeve [1]
Is there any choices?
5 0
3 years ago
Read 2 more answers
Describe how the catalyst, zymase speeds up the reaction shown
Vlad1618 [11]

Describe how the catalyst, zymase speeds up the reaction shown

The catalyst zymase speeds up the reaction by catalyzing the fermentation of sugar into ethanol and carbon dioxide. It is mostly present in yeasts. 

7 0
3 years ago
Other questions:
  • Two methanol-water mixtures are contained in separate tanks. The first mixture contains 40.0 wt% methanol and the second contain
    14·1 answer
  • 3. Which is the minimum amount of energy required to start a chemical reaction?
    5·2 answers
  • Consider the car driving around a circular track .Once stated,the driver maintains a speed 0f 45m/h.Compare the driver's velocit
    9·1 answer
  • PLEASE HELP WITH ENVI SCI QUESTION
    6·1 answer
  • 2 Points<br><br> Which of these is a benefit of using cotton grocery bags?
    11·1 answer
  • Disintegration is the word geologists use for
    5·2 answers
  • Balance the following equations:
    11·1 answer
  • Balance the following equation and determine the coefficients in order
    6·1 answer
  • What is one of the BEST practices officers should use when securing a crime scene?
    8·1 answer
  • State two differences between physical change and chemical change
    10·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!