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nikitadnepr [17]
3 years ago
14

How do you solve 5/6 ×20

Mathematics
1 answer:
Alex73 [517]3 years ago
5 0
Ok so remember that if you had
1/2 times 3/4 that equals (1 ties 3)/(2 times 4)
just mutply top number with top number and bottom number with bottom number so

remember that 20=20/1 so
5/6 times 20/1=
5 times 20=100
6 times 1=6

5/6 times 20/1=100/6 (can be simplified to 50/3 or 16 and 2/3)
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60 pts!!! HELP Find the inverse of the function f(x)= 4/9 x-4<br> show work
earnstyle [38]

Answer:

Inverse Function: f^-1(x) = 9/4x + 9

Step-by-step explanation:

To find  the inverse function we can interchange the position of the variables x and y, and then solve for y;

y = 4/9x - 4 => x = 4/9y - 4,

x = 4/9y - 4,

4/9y = x + 4,

y = 9/4x + 9/4(4),

y = 9/4x + 9/ f^-1(x) = 9/4x + 9

6 0
3 years ago
Graph the function f(x) = (x + 1)(x - 5). Use the drop-
hodyreva [135]

Answer:

3) (2,-9)

4) (0,-5)

5) (1,-8)

Step-by-step explanation:

3)

The vertex will occur between you x-intercepts.

You already found that happens at x=2.

To find the corresponding y-coordinate, replace x in

f(x)=(x+1)(x-5) with 2:

f(2)=(2+1)(2-5)

f(2)=(3)(-3)

f(2)=-9

So the vertex is (2,-9).

4)

The y-intercept is when x=0.

So in f(x)=(x+1)(x-5) replace x with 0:

f(0)=(0+1)(0-5)

f(0)=(1)(-5)

f(0)=-5

So the y-intercept is (0,-5).

5)

To find another point just plug in anything besides any x already used.

We preferably want to use a value of x that will keep us on their grid however far up,down,left, or right their grid goes out. So I'm going to choose something close to the vertex which is at x=2. Let's go with x=1.

So replace x in f(x)=(x+1)(x-5) with x=1:

f(1)=(1+1)(1-5)

f(1)=(2)(-4)

f(1)=-8

So another point to graph is (1,-8).

7 0
3 years ago
What is 4.125 to the nearest whole number?
Elis [28]
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Therefore, if you are trying to round 4.125 to the nearest whole number, you are trying to round it to the ones place, or where the 4 is.  
Because 1<5, 4.125 rounded to the nearest whole number is 4.
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If the length is the same as one leg, than all the other legs should be the same exact dimensions, legs can not be different measurements by height. Hope that this help you!
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Choosing the maximum coverage

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