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3 years ago

How do you solve 5/6 ×20

1 answer:

5 0

Ok so remember that if you had
1/2 times 3/4 that equals (1 ties 3)/(2 times 4)
just mutply top number with top number and bottom number with bottom number so

remember that 20=20/1 so
5/6 times 20/1=
5 times 20=100
6 times 1=6

5/6 times 20/1=100/6 (can be simplified to 50/3 or 16 and 2/3)

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Only one of the comparisons below is correct. Which is correct? What benchmark was used in your answer?

tiny-mole [99]

Answer:

2/3<9/10; I used 3/4 as a benchmark.

Step-by-step explanation:

2/3<1/2; I used 1/2 as a benchmark.

2/3 = 0.(20/3) = 0.667

1/2 = 0.(10/2) = 0.5

So this is wrong, as 0.667 > 0.5.

1/2=3/5; I used 1/4 as a benchmark.

1/2 = 0.(10/2) = 0.5

3/5 = 0.(30/5) = 0.6

0.5 != 0.6, so this is wrong.

2/3<9/10; I used 3/4 as a benchmark.

2/3 = 0.(20/3) = 0.667

9/10 = 0.(90/10) = 0.9

So this is correct, as 0.667 < 0.9

3/4<2/3; I used 1/2 as a benchmark.

3/4 = 0.(30/4) = 0.75

2/3 = 0.(20/3) = 0.667

0.75 > 0.667, so this is wrong.

5 0

3 years ago

Evaluate 10m+n/4 wnen m=5 and n=16

solmaris [256]

Hi!

Let's put the values in the equation.

10 · 5 + 16 ÷ 4 = ?

Using PEMDAS...

Multiplication
50 + 16 ÷ 4 = ?

Division
50 + 4 = ?

Addition
54

The answer is 54

Hope this helps! :)

4 0

3 years ago

Read 2 more answers

Given: f(x) = x + 2<br> [f(x)]^2=

klemol [59]

Answer:

f − 1(x)=x−2 if you are talking about the inverse

please comment what is the purpose of this excersise so i can help you further

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

1.Mr. Bowen’s test is normally distributed with a mean of 75 and a standard deviation of 3 points.

lianna [129]

Answer:

2.28%

Step-by-step explanation:

Mr. bowens test is normally distributed with a mean (μ) of 75 and a standard deviation (σ) of 3 points.

The z score is used in probability to show how many standard deviation is a raw score below or above the mean. The formula for the z score (z) is given by:

$z=\frac{x-\mu}{\sigma}$

For a raw score (x) of 81 points, the z score can be calculated by:

$z=\frac{x-\mu}{\sigma}=\frac{81-75}{3}=2$

Therefore from the normal probability distribution table, the probability that a randomly selected score is greater than 81 can be given as:

P(x > 81) = P(z > 2) = 1 - P(z < 2) = 1 - 0.9772 = 0.0228 = 2.28%

7 0

3 years ago

P=2L+2W<br><br>solve for L <br>do the entire equation

VashaNatasha [74]

$HEY THEIR!!$

Taking commen 2 in RHS
p = 2 (L+W )

Divide by 2 on both sides.
p/2 = L+W

Subtract W on both sides.
p/2 - W = L

or L = p/2- W

HOPE IT HELPS YOU

6 0

3 years ago