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Levart [38]
3 years ago
10

An alpha particle

Physics
1 answer:
nydimaria [60]3 years ago
6 0

An alpha particle  is identical to a helium nucleus ... 2 protons, 2 neutrons. <em>(1)</em>

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After a large snowstorm, you shovel 2,500 kilograms of snow off of your sidewalk in half an hour. You lift
Delvig [45]
Well, the snow has a total weight G=mg=25,000 N. The work is L=Fd=Gh=1.5*25,000=37,500 J. The power is L/t, where t=1800 seconds. P=37,500/1800=20.833 W.
3 0
3 years ago
Which of the following pairings are more likely to be held together with the strong nuclear force?
aivan3 [116]

Which of the following pairings are more likely to be held together with the strong nuclear force

Explanation:

1.What does a strong nuclear force do in an atom? It repels electrons from other electrons. It repels protons from other protons. It attracts protons and neutrons.

2.The chain reaction requires both the release of neutrons from fissile isotopes undergoing nuclear fission and the subsequent absorption of some of these neutrons in fissile isotopes.

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8 0
3 years ago
It takes a car 1.75 h to go from mile marker 115 what's the average speed of the car?
emmainna [20.7K]
The average speed of the car is

               (the mile marker he passes at the end of the 1.75 h) minus 115
divided by
               (1.75 hours) .

The unit is 'miles per hour'.
6 0
3 years ago
Is there a way to see the color of cosmic rays the human eye can't see
KATRIN_1 [288]
You would have to use a machine to convert the colors to one visible by humans or become some other species of animal with a larger light spectrum.
4 0
3 years ago
A sail boat moves north for a distance of 10 km when blown by a wind 30° east of south with the force of 5.00×10^4 N. how much w
erma4kov [3.2K]
<h3><u>Answer;</u></h3>

a) 5.00 x 10^8 J

<h3><u>Explanation;</u></h3>

The work done to move the sailboat is calculated through the equation;

W = F x d

where F is force and d is the distance.

Substituting the known values from the given above,

                             W = (5.00 x 10⁴ N)(10 km)(1000 m/ 1km)

                                 = 5.00 x 10⁸ J

Thus, the work done is <u>5.00 x 10⁸Joules</u>

7 0
3 years ago
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