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4 years ago

Archimedes' principle says that a 15 N object is buoyed up by a force that is

Physics

2 answers:

Afina-wow [57]4 years ago

6 0

Answer:

 equal to the weight of the fluid that the body displaces

Explanation:

Archimides' principle states the definition of buoyant force.

These are the imporant features of the buoyant force that you need to know:

Except for the very special vacuum condition, every body is immersed in a fluid.

The body is subject, at least, to two forces, its weight and the buoyant force.

The weight is the result of the gravitational attraction exerted by the planet, and is equal to the mass of the object by the gravitational acceleration (approximately 9.8 m/s² on Earth). It is directed vertically downward.

The buoyant force is the vertical upward force that the fluid exerts on the object and is equal to the weight of the volume of fluid displaced by the object.

The volume of fluid that the body displaces is equal to the immersed volume of the body.

Fynjy0 [20]4 years ago

5 0

Answer:

an immersed object is buoyed up by force equal to the weight of the fluid it displaces

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Answer:

1.F = 256 N

2.a = 8 m/s/s

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F = ma

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3 years ago

Read 2 more answers

The critical angle for a special type of glass in air is 30.8 ◦ . the index of refraction for water is 1.33. what is the critica

Alina [70]

When light moves from a medium with higher refractive index to a medium with lower refractive index, the critical angle is the angle above which there is no refracted light, and all the light is reflected. The value of this angle is given by
$\theta_c = \arcsin ( \frac{n_2}{n_1} )$
where n2 and n1 are the refractive indices of the second and first medium, respectively.

In the first part of the problem, light moves from glass to air ( $n_a=1.00$ ) and the critical angle is $\theta_c = 30.8^{\circ}$ . This means that we can find the refractive index of glass by re-arranging the previous formula:
$n_g=n_1 = \frac{n_2}{\sin \theta_c}= \frac{1.00}{\sin 30.8^{\circ}}=1.95$

Now the glass is put into water, whose refractive index is $n_w = 1.33$ . If light moves from glass to water, the new critical angle will be
$\theta_c = \arcsin ( \frac{n_2}{n_1} )=\arcsin( \frac{n_w}{n_g} )=\arcsin( \frac{1.33}{1.95} )=\arcsin(0.68)=43.0^{\circ}$

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3 years ago