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Alla [95]
3 years ago
12

The amount of friction divided by the weight of an object forms a unit less number called the

Physics
1 answer:
Romashka [77]3 years ago
3 0

Answer:

Coefficient of friction.

Explanation:

The amount of friction divided by the weight of an object is equal to the coefficient of friction. It is a dimensional less number. It can be given by :

F=\mu N

N is normal force.

\mu = coefficient of friction

\mu=\dfrac{F}{N}

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xxMikexx [17]

Answer:

the last one, the third one, and the first one.

8 0
3 years ago
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You're in a car that gets 28 miles per gallon of gas, driving it at a constant speed. If you took the gas from the car tank, and
Nataly [62]

Answer:

The diameter of the hose is 0.326 mm.

Explanation:

Given that,

Speed of car = 28 miles/galllon

We need to calculate the radius

The rate of flow of fluid is from the equation of continuity

\dfrac{V}{t}=Av

Where, A = area of cross sectional

\dfrac{V}{t}=\pi r^2v

We know that,

The velocity is the ratio of displacement of gas per unit time.

\dfrac{V}{t}=\pi r^\dfrac{x}{t}

\dfrac{V}{x}=\pi r^2

Put the value into the formula

\dfrac{0.00378541}{28\times1609.34}=\pi r^2

r=\sqrt{\dfrac{0.00378541}{28\times1609.34\times\pi}}

r=1.63\times10^{-4}\ m

We need to calculate the diameter of the hose

d = 2r

Put the value of r

d=2\times1.63\times10^{-4}

d=0.326\ mm

Hence, The diameter of the hose is 0.326 mm.

6 0
3 years ago
The comet-hunting astronomer who made a list of over 100 nebulae and galaxies that could be mistaken for comets was Group of ans
Keith_Richards [23]

An Astronomer who made a list of 100 nebulae and galaxies that could

be mistaken for comets was Charles Messer's.

Charles Messier's was a very famous scientist in the field of Astronomy.

His research in appearance of Great comet filled spark to his passion

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  There are various tales of Charles Messiers which put him forward

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5 0
2 years ago
A small bulb is rated at 7.5 W when operated at 125 V. The tungsten filament has a temperature coefficient of resistivity α = 0.
alisha [4.7K]

To solve this problem we will apply the concepts related to resistance as a function of temperature, product of the relationship between the squared voltage and the power. Mathematically this is,

R = \frac{v^2}{P}

Here,

R = Resistance (At function of temperature)

v = Voltage

P = Power

Then we have,

R at 140°C (7 times room temperature),

R(140\°C) = \frac{125^2}{7.5}

R(140\°C) = 2083.33\Omega

The relationship between normal temperature and increased temperature would then be given by,

R(140\°C) = R(20\°C)(1 +\alpha (\Delta T))

R(140\°C) = R(20\°C)(1+(4.5*10^{-3})(140-20))

R(20\°C) = \frac{2083.33}{1.54}

R(20\°C) = 1352.81\Omega

Therefore the correct value of the group of answer is 1350

5 0
3 years ago
A crane with output power of 200W will lift a 600N object a vertical distance of 4.0 meters in seconds
Finger [1]
<span>1 w = 1N/s the change in total energy =mgh = 600*4 = 2400N. 2400N/200N/s = 12seconds </span>
8 0
3 years ago
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