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Svetradugi [14.3K]
3 years ago
13

0÷x=0 pls help it has to be 0 but thats not the answer can't think of anything

Mathematics
1 answer:
sleet_krkn [62]3 years ago
4 0

Answer:

Theres no other answer than 0.

Step-by-step explanation:

I'm sorry!

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CAN SOMEONE HELP MEE
Artist 52 [7]

Answer:

11.45

Step-by-step explanation:

the circumference is 36 so divide it by pie then rounded it to the nearest hundredths place

7 0
3 years ago
For a certain river, suppose the drought length Y is the number of consecutive time intervals in which the water supply remains
AnnZ [28]

Answer:

a) There is a 9% probability that a drought lasts exactly 3 intervals.

There is an 85.5% probability that a drought lasts at most 3 intervals.

b)There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

Step-by-step explanation:

The geometric distribution is the number of failures expected before you get a success in a series of Bernoulli trials.

It has the following probability density formula:

f(x) = (1-p)^{x}p

In which p is the probability of a success.

The mean of the geometric distribution is given by the following formula:

\mu = \frac{1-p}{p}

The standard deviation of the geometric distribution is given by the following formula:

\sigma = \sqrt{\frac{1-p}{p^{2}}

In this problem, we have that:

p = 0.383

So

\mu = \frac{1-p}{p} = \frac{1-0.383}{0.383} = 1.61

\sigma = \sqrt{\frac{1-p}{p^{2}}} = \sqrt{\frac{1-0.383}{(0.383)^{2}}} = 2.05

(a) What is the probability that a drought lasts exactly 3 intervals?

This is f(3)

f(x) = (1-p)^{x}p

f(3) = (1-0.383)^{3}*(0.383)

f(3) = 0.09

There is a 9% probability that a drought lasts exactly 3 intervals.

At most 3 intervals?

This is P = f(0) + f(1) + f(2) + f(3)

f(x) = (1-p)^{x}p

f(0) = (1-0.383)^{0}*(0.383) = 0.383

f(1) = (1-0.383)^{1}*(0.383) = 0.236

f(2) = (1-0.383)^{2}*(0.383) = 0.146

Previously in this exercise, we found that f(3) = 0.09

So

P = f(0) + f(1) + f(2) + f(3) = 0.383 + 0.236 + 0.146 + 0.09 = 0.855

There is an 85.5% probability that a drought lasts at most 3 intervals.

(b) What is the probability that the length of a drought exceeds its mean value by at least one standard deviation?

This is P(X \geq \mu+\sigma) = P(X \geq 1.61 + 2.05) = P(X \geq 3.66) = P(X \geq 4).

We are working with discrete data, so 3.66 is rounded up to 4.

Either a drought lasts at least four months, or it lasts at most thee. In a), we found that the probability that it lasts at most 3 months is 0.855. The sum of these probabilities is decimal 1. So:

P(X \leq 3) + P(X \geq 4) = 1

0.855 + P(X \geq 4) = 1

P(X \geq 4) = 0.145

There is a 14.5% probability that the length of a drought exceeds its mean value by at least one standard deviation

8 0
3 years ago
Ayo can yall help me plzzz
mezya [45]

Answer:

I think it's either Wednesday or Sunday.

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
Please help me, I need an explanation as well please, not just the answer
elena-s [515]
It’s A because if you turn the shape they are the same
7 0
2 years ago
Based on the figure below, what is the value of x? (5 points) A right angle is shown divided in two parts. The measure of the an
Orlov [11]

Answer:

Hello! answer: 9

Step-by-step explanation:

Assuming this is a complementary angle (meaning it will add up to 90 degrees)

5 × 9 = 45 45 + 15 = 60 60 + 30 = 90 therefore x = 9 Hope that helps!

8 0
3 years ago
Read 2 more answers
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