Hi there!
So let's see, we have a die and need to know the probability of rolling a number less than or equal to 4. Let's list the numbers that are less than or equal to 4: 1, 2, 3, 4. Now, since we know that there are 6 numbers on a die and 4 of them are less than or equal to 4, we can set up a fraction to find the percentage. The fraction would be 4/6 because 4 out of the 6 numbers on the die are less than or equal to 6. We can simplify 4/6 to 2/3 as well. To find the percentage, all we need to do is divide the numerator by the denominator. This leaves us with approximately 66.66%.
Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
Answer:
61.27 cm
Step-by-step explanation:
(3.14)(11)(0.5) = 17.27
2+2+20+9+11+17.27 = 61.27
Since as of now we're saying that the probability of having a girl is 1/2, we can say:
1/2 * 1/2 * 1/2 * 1/2, because then you're saying a one half chance of having a girl times another one half chance of having a girl, etc.
That ends up to be 1/16.
Answer:
y=[-4]x+[10]
Step-by-step explanation:
For a line to be perpendicular to another it must have the reverse reciprocal of the opposite line, to find the reverse reciprocal you take your slope, flip the numerator and denominator, and multiply it by -1.
The slope 
turns into 
and is then multiplied by -1 to become 
which can be simplified down to: 
Now that we know the slope we need the line to pass through a point, so we will use point slope form:
Substitute in our slope and point values:
Now solve for y:
Then you will find that line 
runs perpendicular to 
and intersects point (2,2).
Please note that your x^3/4 is ambiguous. Did you mean (x^3) divided by 4
or did you mean x to the power (3/4)? I will assume you meant the first, not the second. Please use the "^" symbol to denote exponentiation.
If we have a function f(x) and its derivative f'(x), and a particular x value (c) at which to begin, then the linearization of the function f(x) is
f(x) approx. equal to [f '(c)]x + f(c)].
Here a = c = 81.
Thus, the linearization of the given function at a = c = 81 is
f(x) (approx. equal to) 3(81^2)/4 + [81^3]/4
Note that f '(c) is the slope of the line and is equal to (3/4)(81^2), and f(c) is the function value at x=c, or (81^3)/4.
What is the linearization of f(x) = (x^3)/4, if c = a = 81?
It will be f(x) (approx. equal to)
