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vova2212 [387]
2 years ago
5

Easy + brainliest 2x(^3) + 10x(^2) − 4x(^2)y − 20xy factor this pls, (show all work)

Mathematics
2 answers:
Dimas [21]2 years ago
7 0

Answer:

Answer:

2x • (x2 - 2xy + 5x - 10y)

Step-by-step explanation:

Step  1  :

Equation at the end of step  1  :

(((2•(x3))+(10•(x2)))-(22x2•y))-20xy

Step  2  :

Equation at the end of step  2  :

(((2 • (x3)) +  (2•5x2)) -  22x2y) -  20xy

Step  3  :

Equation at the end of step  3  :

((2x3 +  (2•5x2)) -  22x2y) -  20xy

Step  4  :

Step  5  :

Pulling out like terms :

5.1     Pull out like factors :

 2x3 - 4x2y + 10x2 - 20xy  =

2x • (x2 - 2xy + 5x - 10y)

Final result :

2x • (x2 - 2xy + 5x - 10y)

Step-by-step explanation:

ipn [44]2 years ago
5 0

Answer:

2x • (x2 - 2xy + 5x - 10y)

Step-by-step explanation:

Step  1  :

Equation at the end of step  1  :

 (((2•(x3))+(10•(x2)))-(22x2•y))-20xy

Step  2  :

Equation at the end of step  2  :

 (((2 • (x3)) +  (2•5x2)) -  22x2y) -  20xy

Step  3  :

Equation at the end of step  3  :

 ((2x3 +  (2•5x2)) -  22x2y) -  20xy

Step  4  :

Step  5  :

Pulling out like terms :

5.1     Pull out like factors :

  2x3 - 4x2y + 10x2 - 20xy  =

 2x • (x2 - 2xy + 5x - 10y)

Final result :

 2x • (x2 - 2xy + 5x - 10y)

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\quad \huge \quad \quad \boxed{ \tt \:Answer }

\qquad \tt \rightarrow \: \{ 0,4 \}

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\large \tt Solution  \: :

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