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vova2212 [387]
3 years ago
5

Easy + brainliest 2x(^3) + 10x(^2) − 4x(^2)y − 20xy factor this pls, (show all work)

Mathematics
2 answers:
Dimas [21]3 years ago
7 0

Answer:

Answer:

2x • (x2 - 2xy + 5x - 10y)

Step-by-step explanation:

Step  1  :

Equation at the end of step  1  :

(((2•(x3))+(10•(x2)))-(22x2•y))-20xy

Step  2  :

Equation at the end of step  2  :

(((2 • (x3)) +  (2•5x2)) -  22x2y) -  20xy

Step  3  :

Equation at the end of step  3  :

((2x3 +  (2•5x2)) -  22x2y) -  20xy

Step  4  :

Step  5  :

Pulling out like terms :

5.1     Pull out like factors :

 2x3 - 4x2y + 10x2 - 20xy  =

2x • (x2 - 2xy + 5x - 10y)

Final result :

2x • (x2 - 2xy + 5x - 10y)

Step-by-step explanation:

ipn [44]3 years ago
5 0

Answer:

2x • (x2 - 2xy + 5x - 10y)

Step-by-step explanation:

Step  1  :

Equation at the end of step  1  :

 (((2•(x3))+(10•(x2)))-(22x2•y))-20xy

Step  2  :

Equation at the end of step  2  :

 (((2 • (x3)) +  (2•5x2)) -  22x2y) -  20xy

Step  3  :

Equation at the end of step  3  :

 ((2x3 +  (2•5x2)) -  22x2y) -  20xy

Step  4  :

Step  5  :

Pulling out like terms :

5.1     Pull out like factors :

  2x3 - 4x2y + 10x2 - 20xy  =

 2x • (x2 - 2xy + 5x - 10y)

Final result :

 2x • (x2 - 2xy + 5x - 10y)

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The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The attached Excel file 2013 NCAA BB Tournament shows the salaries paid to the coaches of 62 of the 68 teams in the 2013 NCAA basketball tournament (not all private schools report their coach's salaries). Consider these 62 salaries to be a sample from the population of salaries of all 346 NCAA Division I basketball coaches.

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Question 2. Coach Mike Krzyzewski's high salary is an outlier and could be significantly affecting the confidence interval results. Remove Coach Krzyzewski's salary from the data and recalculate the 95% confidence interval using the remaining 61 salaries.

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Answer:

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upper bound of confidence interval = $1,807,477

Question 2:

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Step-by-step explanation:

Question 1:

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The t-score corresponding to a 95% confidence level is  

Significance level = α = 1 - 0.95 = 0.05/2 = 0.025  

Degree of freedom = n - 1 = 62 - 1 = 61

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CI = \bar{x} \pm t_{\alpha/2}(\frac{s}{\sqrt{n} } ) \\\\CI = 1,465,752 \pm 1.999 \cdot (\frac{1,346,046.2}{\sqrt{62} } ) \\\\CI = 1,465,752 \pm 1.999 \cdot (170948.04 ) \\\\CI = 1,465,752 \pm 341,725 \\\\LCI = 1,465,752 - 341,725 = 1,124,027 \\\\UCI = 1,465,752 + 341,725 = 1,807,477\\\\

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The sample mean salary of 61 couches is

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The standard deviation of the mean salary is

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t-score = 2.001

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