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2 years ago

Easy + brainliest 2x(^3) + 10x(^2) − 4x(^2)y − 20xy factor this pls, (show all work)

Mathematics

2 answers:

Dimas [21]2 years ago

7 0

Answer:

Answer:

2x • (x2 - 2xy + 5x - 10y)

Step-by-step explanation:

Step 1 :

Equation at the end of step 1 :

(((2•(x3))+(10•(x2)))-(22x2•y))-20xy

Step 2 :

Equation at the end of step 2 :

(((2 • (x3)) + (2•5x2)) - 22x2y) - 20xy

Step 3 :

Equation at the end of step 3 :

((2x3 + (2•5x2)) - 22x2y) - 20xy

Step 4 :

Step 5 :

Pulling out like terms :

5.1 Pull out like factors :

2x3 - 4x2y + 10x2 - 20xy =

2x • (x2 - 2xy + 5x - 10y)

Final result :

2x • (x2 - 2xy + 5x - 10y)

Step-by-step explanation:

ipn [44]2 years ago

5 0

Answer:

2x • (x2 - 2xy + 5x - 10y)

Step-by-step explanation:

Step 1 :

Equation at the end of step 1 :

(((2•(x3))+(10•(x2)))-(22x2•y))-20xy

Step 2 :

Equation at the end of step 2 :

(((2 • (x3)) + (2•5x2)) - 22x2y) - 20xy

Step 3 :

Equation at the end of step 3 :

((2x3 + (2•5x2)) - 22x2y) - 20xy

Step 4 :

Step 5 :

Pulling out like terms :

5.1 Pull out like factors :

2x3 - 4x2y + 10x2 - 20xy =

2x • (x2 - 2xy + 5x - 10y)

Final result :

2x • (x2 - 2xy + 5x - 10y)

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$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \: \{ 0,4 \}$

____________________________________

$\large \tt Solution \: :$

$\qquad \tt \rightarrow \: - {a}^{2} + 4a = 0$

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The two cases are :

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