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Dmitry_Shevchenko [17]
4 years ago
7

Why doesn’t the Moon crash into the Earth or the Earth crash into the Sun?

Physics
2 answers:
pochemuha4 years ago
8 0
Because the gravity isn't very intesity

Sunny_sXe [5.5K]4 years ago
6 0
Same reason we don't fall into the Sun<span>. We are ... On the other hand, it </span>doesn't crash into the Earth<span> because it has a tangential velocity (like swinging a yo-yo around yourself).</span>
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9.58 A spring of equilibrium length L1 and spring constant k1 hangs from the ceiling. Mass m1 is suspended from its lower end. T
andrey2020 [161]

Answer:

The distance of m2 from the ceiling is L1 +L2 + m1g/k1 + m2g/k1 + m2g/k2.

See attachment below for full solution

Explanation:

This is so because the the attached mass m1 on the spring causes the first spring to stretch by a distance of m1g/k1 (hookes law). This plus the equilibrium lengtb of the spring gives the position of the mass m1 from the ceiling. The second mass mass m2 causes both springs 1 and 2 to stretch by an amout proportional to its weight just like above. The respective stretchings are m2g/k1 for spring 1 and m2g/k2 for spring 2. These plus the position of m1 and the equilibrium length of spring 2 L2 gives the distance of L2 from the ceiling.

4 0
4 years ago
A high-speed K0 meson is traveling at β = 0.90 when it decays into a π + and a π − meson. What are the greatest and least speeds
san4es73 [151]

Answer:

greatest speed=0.99c

least speed=0.283c

Explanation:

To solve this problem, we have to go to frame of center of mass.

Total available energy fo π + and π - mesons will be difference in their rest energy:

E_{0,K_{0} }-2E_{0,\pi }  =497Mev-2*139.5Mev\\

                       =218 Mev

now we have to assume that both meson have same kinetic energy so each will have K=109 Mev from following equation for kinetic energy we have,

K=(γ-1)E_{0,\pi }

K=E_{0,\pi}(\frac{1}{\sqrt{1-\beta ^{2} } } -1)\\\frac{1}\sqrt{1-\beta ^{2} }}=\frac{K}{E_{0,\pi}}+1\\   {1-\beta ^{2}=\frac{1}{(\frac{K}{E_{0,\pi}}+1)^2}}\\\beta ^{2}=1-\frac{1}{(\frac{K}{E_{0,\pi}}+1)^2}}\\\beta = +-\sqrt{\frac{1}{(\frac{K}{E_{0,\pi}}+1)^2}}\\\\\\beta =+-\sqrt{1-\frac{1}{(\frac{109Mev}{139.5Mev+1)^2}}

u'=+-0.283c

note +-=±

To find speed least and greatest speed of meson we would use relativistic velocity addition equations:

u=\frac{u'+v}{1+\frac{v}{c^{2} } } u'\\u_{max} =\frac{u'_{+} +v_{} }{1+\frac{v}{c^{2} } } u'_{+} \\u_{max} =\frac{0.828c +0.9c }{1+\frac{0.9c}{c^{2} } } 0.828\\ u_{max} =0.99c\\u_{min} =\frac{u'_{-} +v_{} }{1+\frac{v}{c^{2} } } u'_{-}\\u_{min} =\frac{-0.828c +0.9c }{1+\frac{0.9c}{c^{2} } } -0.828c\\u_{min} =0.283c

6 0
3 years ago
Which of the following statements best explains why liquid water is NOT found on Jupiter?
agasfer [191]

Answer:

The planet lacks a solid surface and the temperature is too low

Explanation:

Jupiter does not have solid surface as it is made up of swirling gases, mainly hydrogen(90%) and helium(~10%). The swirl comes from massive wind with speed of 335 miles/hour. The temperature in cloud of Jupiter is 145°C which is too low for water to remain in liquid state as the temperature range for liquid water is 0°C to 100°C.

6 0
3 years ago
The diagram shows a motion map for a train. A motion map. The position line is a long black arrow pointing right that is labeled
Elis [28]

Answer:

the train stopped for 3 seconds

Explanation:

5 0
3 years ago
Interstellar space (far from any stars) contains atomic hydrogen (H) with a density of 1 atom/cm3 and at a temperature of about
Mandarinka [93]

Explanation:

Given that,

Number density n= 1\ atom/cm^{3} =10^{6}\ atom/m^3

Temperature = 2.7 K

(a). We need to calculate the pressure in interstellar space

Using ideal gas equation

PV=nRT

P=\dfrac{nRT}{V}

P=\dfrac{10^{6}\times8.314\times2.7}{6.023\times10^{23}}

P=3.727\times10^{-17}\ Pa

P=36.78\times10^{-23}\ atm

The pressure in interstellar space is 36.78\times10^{-23}\ atm

(b). We need to calculate the root-mean square speed of the atom

Using formula of rms

v_{rms}=\sqrt{\dfrac{3RT}{Nm}}

Put the value into the formula

v_{rms}=\sqrt{\dfrac{3\times8.314\times2.7}{1.007\times10^{-3}}}

v_{rms}=258.6\ m/s

The root-mean square speed of the atom is 258.6 m/s.

(c). We need to calculate the  kinetic energy

Average kinetic energy of atom

E=\dfrac{3}{2}kT

Where, k = Boltzmann constant

Put the value into the formula

E=\dfrac{3}{2}\times1.38\times10^{-23}\times2.7

E=5.58\times10^{-23}\ J

The kinetic energy stored in 1 km³ of space is 5.58\times10^{-23}\ J.

Hence, This is the required solution.

7 0
3 years ago
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