Answer:
The Gravitational force is the answer.
D=Vot+1/2at^2
In this case, there is no initial y velocity so the term Vot=0 so d=1/2at^2
acceleration=acceleration due to gravity=-9.8m/s^2
It falls - 22cm or -0.22m
We have - 0.22=1/2(-9.8)t^2
t^2=(-0.44)/(-9.8)
t=sqrt[0.44/9.8]
For conservation of energy we have to:
mgH=mv²/2
Clearing
<span> v=sqrt(2gH)
Then, by definition
</span><span> F=Δp/Δt= Δ(mv)/ Δt=m Δ(v)/Δt=
</span> =m[sqrt(2gH)-0]/Δt= m[sqrt(2gH)]/ Δt
the answer is
F=m[sqrt(2gH)]/ Δt
Answer:
2.933 kg m/s
Explanation:
impulse = change in momentum
impulse = mass ( final velocity - initial velocity )
= 0.0459 ( 63.9 - 0 )
= 0.0459 × 63.9
= 2.93301 kg m/s
or = 2.933 kg m/s up to 4 significant figures
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