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3 years ago

How many atoms are in 4.93 moles hcl?

Chemistry

1 answer:

trasher [3.6K]3 years ago

4 0

1 mole ------------- 6.02x10²³ atoms
4.93 moles ------- ??

4.93 x ( 6.02x10²³) / 1 =

=> 2.96x10²⁴ atoms

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Equation for the reaction of water and HCL(g)

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HCl + H2O---> H3O+ Cl-

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3 years ago

BRAINLIEST TO WHOEVER ANSWERS CORRECTLY FIRST!

Alenkasestr [34]

Answer:

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Explanation:

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_______________ is when a compound containing carbon and hydrogen (and sometimes oxygen) combines with oxygen gas to produce car

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Answer:

C. Combustion

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3 years ago

For the n = 3 electron shell, which of the following quantum numbers are valid? Check all that apply.

stealth61 [152]

Answer:

The valid quantum numbers are l=0, l=-2 and l= 2.

Explanation:

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n = 3 electron shell

Suppose, the valid quantum numbers are

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m = –2

l = –1

m = 2

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The value of n = 3

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Then the principal quantum number is 3. Which is shows the M shell.

So, n = 3

Azimuthal quantum number :

The azimuthal quantum number is l.

$l=0,1,2$

Magnetic quantum number :

The magnetic quantum number is

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Hence, The valid quantum numbers are l=0, l=-2 and l= 2.

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3 years ago

Read 2 more answers

Consider the following reaction: NaHCO3 + HC2H3O2 → NaC2H3O2 + H2O + CO2 How many g of CO2 would be produced from the complete r

Alenkasestr [34]

<h2>1.25 g of $CO_2$ would be produced from the complete reaction of 25 mL of 0.833 mol/L $HC_3H_3O_2$ with excess $NaHCO_3$ </h2>

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in L)}}$

$0.833M=\frac{\text{Moles of} HC_3H_3O_2\times 1000}{25ml}\\\\\text{Moles of} HC_3H_3O_2 =\frac{0.833mol/L\times 25}{1000}=0.0208mol$

$NaHCO_3+HC_2H_3O_2\rightarrow NaC_2H_3O_2+H_2O+CO_2$

According to stoichiometry:

1 mole of $HC_2H_3O_2$ will give = 1 mole of $CO_2$

0.0208 moles of $HC_2H_3O_2$ will give = $\frac{1}{1}\times 0.0208=0.0208 moles$ of $CO_2$

Mass of $HC_2H_3O_2=moles\times {\text {molar mass}}=0.0208\times 60g/mol=1.25g$

Thus 1.25 g of $CO_2$ would be produced from the complete reaction of 25 mL of 0.833 mol/L $HC_3H_3O_2$ with excess $NaHCO_3$

Learn more about molarity

https://brainly.in/question/13034158

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5 0

3 years ago