Question

Be sure to answer all parts.The equilibrium constant (Kc) for the formation of nitrosyl chloride, an orange-yellow compound, from nitric oxide and molecular chlorine 2NO(g) + Cl2(g) ⇌ 2NOCl(g) is 1 × 107 at a certain temperature. In an experiment, 4.40 × 10−2 mole of NO, 1.80 × 10−3 mole of Cl2, and 9.50 moles of NACl are mixed in a 2.60−L flask. What is Qc for the experiment

Answer 1

Explanation:

Since, the given reaction is as follows.

       $2NO(g) + Cl_{2} \rightleftharpoons 2NOCl$

Expression for $Q_{c}$ of this reaction is as follows.

       $Q_{c} = \frac{[NOCl]^{2}}{[NO]^{2}[Cl_{2}]}$

Putting the given values into the above formula as follows.

       $Q_{c} = \frac{[NOCl]^{2}}{[NO]^{2}[Cl_{2}]}$

               = $\frac{(9.50)^{2}}{(4.40 \times 10^{-2})^{2} \times (1.80 \times 10^{-3})}$

               = $\frac{90.25}{34.848 \times 10^{-7}}$

              = $2.59 \times 10^{-7}$

Thus, we can conclude that $Q_{c}$ for the experiment is $2.59 \times 10^{-7}$.