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Finger [1]
3 years ago
7

Francium has the largest atomic radius. Why might this be?

Chemistry
1 answer:
Lerok [7]3 years ago
6 0
The answer is B
Basically the atomic radius increases when the energy levels and the groups increase .Having the most nuclear pull creates a force of attraction that pulls the electrons closer to the nucleus , resulting in a smaller atomic radius.
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Among these element groups, which is least likely to form ions?
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Your answer would be 7A

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3 years ago
Please provide thorough explanation
Arlecino [84]

Possible products in this reaction are the products 2 and 3.

<h3>What is the Friedel Crafts reaction?</h3>

The Friedel Crafts reaction is one in which the electrophile is created by a Lewis acid reaction between the AlCl3 and the alkylhalide reactant .

Now we know that there is the possibility of two products in this reaction due to a resonance shift as such possible products in this reaction are the products 2 and 3.

Learn more about Friedel Crafts reaction:brainly.com/question/14993566?

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1 year ago
An object floats im sea water more readily because of sea water’s
Taya2010 [7]
Because of the sea waters density. If an object is less dense than the water it would not float
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Answer is: detergent is basic.

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Calculate the time needed for a constant current of 0.961 a to deposit 0.500 g of co(ii) as
Vera_Pavlovna [14]

1.70 × 10³ seconds

<h3>Explanation </h3>

\text{Co}^{2+} + 2 e⁻ → \text{Co}

It takes two moles of electrons to reduce one mole of cobalt (II) ions and deposit one mole of cobalt.

Cobalt has an atomic mass of 58.933 g/mol. 0.500 grams of Co contains 0.500 / 58.933 = 8.484\times 10^{-3} \; \text{mol} of Co atoms. It would take 2 \times 8.484 \times 10^{-3} = 0.01697 \; \text{mol} of electrons to reduce cobalt (II) ions and produce the 8.484\times 10^{-3} \; \text{mol} of cobalt atoms.

Refer to the Faraday's constant, each mole of electrons has a charge of around 96 485 columbs. The 0.01697 mol of electrons will have a charge of 1.637 \times 10^{3} \; \text{C}. A current of 0.961 A delivers 0.961 C of charge in one single second. It will take 1.637 \times 10^{3} / 0.961 = 1.70 \times 10^{3} \; \text{s} to transfer all these charge and deposit 0.500 g of Co.

4 0
3 years ago
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