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3 years ago

Francium has the largest atomic radius. Why might this be?

1 answer:

6 0

The answer is B
Basically the atomic radius increases when the energy levels and the groups increase .Having the most nuclear pull creates a force of attraction that pulls the electrons closer to the nucleus , resulting in a smaller atomic radius.

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Hello how to draw the electron dot structure of H2S and F2?

lidiya [134]

Explanation:

1. Attachment

Electron dot structure of H2S (hydrogen sulfide)

2. Attachment

Electron dot structure of F2 (Fluorine).

5 0

3 years ago

QUESTION 1 The ____________________ fan switch is nothing more than a thermostat that closes on a rise in temperature to start t

AVprozaik [17]

Answer:

temperature controlled

7 0

3 years ago

(Thermodynamics)

frutty [35]

Answer:

3853 g

Step-by-step explanation:

M_r: 107.87

16Ag + S₈ ⟶ 8Ag₂S; ΔH°f = -31.8 kJ·mol⁻¹

1. Calculate the moles of Ag₂S

Moles of Ag₂S = 567.9 kJ × 1 mol Ag₂S/31.8kJ = 17.858 mol Ag₂S

2. Calculate the moles of Ag

Moles of Ag = 17.86 mol Ag₂S × (16 mol Ag/8 mol Ag₂S) = 35.717 mol Ag

3. Calculate the mass of Ag

Mass of g = 35.717 mol Ag × (107.87 g Ag/1 mol Ag) = 3853 g Ag

You must react 3853 g of Ag to produce 567.9 kJ of heat

3 0

3 years ago

Someone answer the limited regent...

OleMash [197]

Answer:

20 g Ag

General Formulas and Concepts:

Chemistry - Stoichiometry

Using Dimensional Analysis

Chemistry - Atomic Structure

Reading a Periodic Table

Explanation:

Step 1: Define

[RxN] Cu (s) + AgNO₃ (aq) → CuNO₃ (aq) + Ag (s)

[Given] 10 g Cu

Step 2: Identify Conversions

[RxN] 1 mol Cu = 1 mol Ag

Molar Mass of Cu - 63.55 g/mol

Molar Mass of Ag - 197.87 g/mol

Step 3: Stoichiometry

$10 \ g \ Cu(\frac{1 \ mol \ Cu}{63.55 \ g \ Cu})(\frac{1 \ mol \ Ag}{1 \ mol \ Cu} )(\frac{197.87 \ g \ Ag}{1 \ mol \ Ag} )$ = 16.974 g Ag

Step 4: Check

We are given 1 sig fig. Follow sig fig rules and round.

16.974 g Ag ≈ 20 g Ag

6 0

3 years ago

Is this equation completely balanced? 2C8H8 + 25O2 8CO2 + 18H2O No, because the number of carbon, hydrogen & oxygen atoms on

Sergio039 [100]

So to make it clear let's break the equation down species by species and assess the number of each species on bothe sides of the equation:
2C₈H₈ + 25O₂ → 8CO₂ + 18H₂O
LHS: C - 16 RHS: C - 8
H - 16 H - 36
O - 50 O - 34

Thus based on that it is evident that the equation is not quite balanced. This therefore means a "No, because the number of carbon, hydrogen & oxygen atoms on both sides of the equation are not equal."

The actual balance equation would be C₈H₈ + 10O₂ → 8CO₂ + 4H₂O

8 0

3 years ago