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coldgirl [10]
3 years ago
15

Courtney camino desde su casa a la playa a una velocidad constante de 4 kilómetros por hora, y luego de la

Mathematics
1 answer:
Zepler [3.9K]3 years ago
7 0

Answer:

The system of equations represents this situation is:

4<em>b</em> + 5<em>p </em>= 8 and <em>b</em> + <em>p</em> = 2.

Step-by-step explanation:

The question is:

Courtney walked from her house to the beach at a constant speed of 4 kilometres per hour, and after  beach to the park at a constant speed of 5 kilometres per hour. The entire walk took 2 hours and  the total distance Courtney traveled was 8 kilometres.  Let b be the number of hours it took Courtney to walk from her house to the beach and let p be the number of hours  it took him to walk from the beach to the park.  Which system of equations represents this situation?

Solution:

The formula to speed is:

s=\frac{d}{t}

Then the formula of distance traveled is:

d=st

Let the two distances traveled by Courtney be, <em>d</em>₁ and <em>d</em>₂.

It is provided that:

Speed at Courtney walked from her house to the beach was, <em>s</em>₁ = 4 km/h.

Speed at Courtney walked from the beach to the park was, <em>s</em>₂ = 5 km/h.

The total distance traveled is,

<em>d</em>₁ + <em>d</em>₂ = 8...(i)

It is assumed that,

<em>b</em> =  number of hours it took Courtney to walk from her house to the beach

<em>p</em> = number of hours  it took him to walk from the beach to the park

Then the equation (i) can be written as:

<em>bs</em>₁ + <em>ps</em>₂ = 8

⇒ 4<em>b</em> + 5<em>p </em>= 8

Also the total time it took to travel 8 kilometres is 2 hours.

Then,

\frac{d_{1}}{s_{1}}+\frac{d_{2}}{s_{2}}=2\\\frac{bs_{1}}{s_{1}}+\frac{ps_{2}}{s_{2}}=2\\b+p=2

Thus, the system of equations represents this situation is:

4<em>b</em> + 5<em>p </em>= 8 and <em>b</em> + <em>p</em> = 2.

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