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makkiz [27]
3 years ago
11

An electric scooter has a battery capable of supplying 135 Wh of energy. If friction forces and other losses account for 60.0% o

f the energy usage, what altitude change can a rider achieve when driving in hilly terrain, if the rider and scooter have a combined weight of 945 N?
Physics
1 answer:
Vedmedyk [2.9K]3 years ago
7 0

Answer:

206 m

Explanation:

The energy output of the scooter battery = 135 Wh = 135 W × 3600 s = 486000 J.

If 60.0% accounts for losses, then

useful energy = (100 - 60)% of 486000 J = 40% × 486000 J = 194400 J

The energy needed to move through an altitude = product of weight and altitude

E=F\times h

h = \dfrac{E}{F} = \dfrac{194400\text{ J}}{945\text{ N}} = 206\text{ m}

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Answer:

Explanation:

First we need to determine the distance covered during deceleration. According to the equation of motion.

S = ut+1/2at²

Given:

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a = -10m/s (deceleration is negative acceleration)

S = 20²+1/2(-10)(0.5)²

S = 400-5(0.5)²

S = 400-5(0.25)

S = 400-1.25

S = 398.75m

If the deer steps onto the road 35m in front of you, the distance between you and the deer when you come to a stop will be 398.75-35 = 363.75m

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A 40 kg dog is sitting on top of a hillside and has a potential energy of 1,568 J. What is the height of the hillside? (Formula:
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The answer is 4.0 m

Explanation:

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Maya and Kenzie are discussing oil spills and how they impact the environment. How can humans help reduce the impact of oil spil
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A branch falls from a tree How fast is the branch moving after 0 28 seconds
egoroff_w [7]

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c. 2.7 m/s

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If the resistance of dry skin is 200 times larger than the resistance of wet skin, how do the maximum voltages without shock com
Lelu [443]

Answer:

<em> B) The voltage on dry skin needs to be 200 times larger than the voltage on wet skin.</em>

<em></em>

Explanation:

This is the complete question

A person will feel a shock when a current of greater than approximately 100μ A flows between his index finger and thumb. If the resistance of dry skin is 200 times larger than the resistance of wet skin, how do the maximum voltages without shock compare in each scenario?

A) The voltage on dry skin needs to be 200 times smaller than the voltage on wet skin.

B) The voltage on dry skin needs to be 200 times larger than the voltage on wet skin.

C) The voltage on dry skin is the same as the voltage on wet skin.

D) The voltage on dry skin needs to be 40,000 times larger than the voltage on wet skin.

Ohm's law states that electric current is proportional to voltage and inversely proportional to resistance.

the equation is written as

V = IR

Where V is the voltage

I is the current

R is the resistance

for this case, the current I is 100μ A = 100 x 10^16 A

resistance of wet skin = R

resistance of dry skin = 200R

for the wet skin, voltage will be

V = IR = 100*10^{-6} R

for dry skin, voltage will be

V = IR = 100*10^{-6}*200R = 0.02R

Comparing both voltages

0.02R ÷  100*10^{-6} R  = 200

<em>this means that the voltage on the wet skin should be 200 times lesser than the voltage on the dry skin or the voltage on the dry skin should be 200 times more than the voltage on the wet skin.</em>

4 0
4 years ago
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